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loris [4]
3 years ago
14

Write the two consecutive whole numbers that the quotient for 96÷19 is between

Mathematics
1 answer:
natka813 [3]3 years ago
6 0
96 divided by 19 is 5.05263157895<span>, so it would be in between 5 and 6!</span>
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swat32
You can use sin cos or tan to solve this
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3 years ago
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Probability scenarios?
velikii [3]

Here are some probability scenarios.

- Flipping a coin and seeing if it is heads or tails.

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4 0
3 years ago
HELP ASAP!! WILL MARK AS BRAINLIEST IF ANSWERED NOW!!!!
tiny-mole [99]

Answer: She should blend 98 lbs of high-quality beans.

She should blend 72 lbs of cheaper beans

Step-by-step explanation:

Let x represent the number of pounds of high quality beans that she should blend.

Let y represent the number of pounds of cheaper beans that she should blend.

She needs to prepare 170 lbs of blended coffee beans. This means that

x + y = 170

She plans to do this by blending together a high-quality bean costing $4.75 per pound and a cheaper bean at $2.00 per pound. The blend would sell for $3.59 per pound. This means that the total cost of the blend would be 3.59×170 = $610.3. This means that

4.75x + 2y = 610.3 - - - - - - - - - -1

Substituting x = 170 - y into equation 1, it becomes

4.75(170 - y) + 2y = 610.3

807.5 - 4.75y + 2y = 610.3

- 4.75y + 2y = 610.3 - 807.5

- 2.75y = - 197.2

y = - 197.2/-2.75 = 71.9

y = 72 pounds

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4 0
3 years ago
Find the smallest positive integer n such that the digit sum of n is divisible by 5, and the digit sum of n +1 is also divisible
alisha [4.7K]

Answer:

139,999

Step-by-step explanation:

If the digit sum of n is divisible by 5, the digit sum of n+1 can't physically be divisble by 5, unless we utilise 9's at the end, this way whenever we take a number in the tens (i.e. 19), the n+1 will be 1 off being divisble, so if we take a number in the hundreds, (109, remember it must have as many 9's at the end as possible) the n+1 will be 2 off being divisble, so continuing this into the thousands being three, tenthousands being 4, the hundred thousands will be 5 off (or also divisble by 5). So if we stick a 1 in the beginning (for the lowest value), and fill the last digits with 9's, we by process of elimination realise that the tenthousands digit must be 3 such that the digit sum is divisible by 5, therefore we get 139,999

6 0
2 years ago
What is the value of the expression? negative two to the sixth power -(six) to the second power Enter your answer in the box.
ziro4ka [17]
-2 ^ 6            -6 ^ 2        .............
  -64                -36
5 0
3 years ago
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