You can use sin cos or tan to solve this
Here are some probability scenarios.
- Flipping a coin and seeing if it is heads or tails.
- Thinking to yourself: "Is it going to rain or hail?"
- Spinning a spinner and seeing what color it lands on.
- Probability in winning the lottery.
- Having 5 pairs of black shoes and one pair of yellow shoes.
The probability of picking the yellow shoe is 1/5.
There are lots of more examples out there!
<em>Hope helps!-Aparri </em>
Answer: She should blend 98 lbs of high-quality beans.
She should blend 72 lbs of cheaper beans
Step-by-step explanation:
Let x represent the number of pounds of high quality beans that she should blend.
Let y represent the number of pounds of cheaper beans that she should blend.
She needs to prepare 170 lbs of blended coffee beans. This means that
x + y = 170
She plans to do this by blending together a high-quality bean costing $4.75 per pound and a cheaper bean at $2.00 per pound. The blend would sell for $3.59 per pound. This means that the total cost of the blend would be 3.59×170 = $610.3. This means that
4.75x + 2y = 610.3 - - - - - - - - - -1
Substituting x = 170 - y into equation 1, it becomes
4.75(170 - y) + 2y = 610.3
807.5 - 4.75y + 2y = 610.3
- 4.75y + 2y = 610.3 - 807.5
- 2.75y = - 197.2
y = - 197.2/-2.75 = 71.9
y = 72 pounds
x = 170 - y = 170 - 71.9
x = 98.1
x = 98 pounds
Answer:
139,999
Step-by-step explanation:
If the digit sum of n is divisible by 5, the digit sum of n+1 can't physically be divisble by 5, unless we utilise 9's at the end, this way whenever we take a number in the tens (i.e. 19), the n+1 will be 1 off being divisble, so if we take a number in the hundreds, (109, remember it must have as many 9's at the end as possible) the n+1 will be 2 off being divisble, so continuing this into the thousands being three, tenthousands being 4, the hundred thousands will be 5 off (or also divisble by 5). So if we stick a 1 in the beginning (for the lowest value), and fill the last digits with 9's, we by process of elimination realise that the tenthousands digit must be 3 such that the digit sum is divisible by 5, therefore we get 139,999
