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3 years ago

F(x)=-2x+1; {-2,0,2,4,6} Find the range of the function for the given domain.

Mathematics

1 answer:

3241004551 [841]3 years ago

4 0

Answer:

For the domain indicated, the range is {-11, -7, -3, 1, 5}

Step-by-step explanation:

Given the indicated domain of f(x) you have to replace the values in the function to find the range (the "y" values of the function).

f(-2) = 5

f(0) = 1

f(2) = -3

f(4) = -7

f(6) = -11.

So the range for this domain is {-11, -7, -3, 1, 5}

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Please help and show all work thank you.

borishaifa [10]

Question 1:

We can tell that this shape is a parallelogram because the diagonals bisect each other, which is a property unique to parallelograms.

Question 2:

72 + 72 = 144

This is not a right angle, so this shape cannot be a square or rectangle.

Since we have congruent base angles, each of those triangles are congruent isosceles triangles.

Thus, we have 4 sides of equal length. Thus, this shape must be a rhombus.

Question 3:

We know that AB and CD (the legs) are congruent since this is an isosceles trapezoid.

8y - 18 = 7y - 4

Subtract both sides by 7y

y - 18 = -4

Add both sides by 18

y = 14

That's your answer.

Have an awesome day! :)

3 0

3 years ago

HELP WILL GIVE BRANLIEST!

o-na [289]

Answer:

Step-by-step explanation:

7 0

2 years ago

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 29 ft/s. Its height

Ilia_Sergeevich [38]

Answer:

$\overline{v}_{@\Delta t=0.01s}=-15.22ft/s, \overline{v}_{@\Delta t=0.005s}=-15.11ft/s, \overline{v}_{@\Delta t=0.002s}=-15.044ft/s, \overline{v}_{@\Delta t=0.001s}=-15.022ft/s$

Step-by-step explanation:

Now, in order to solve this problem, we need to use the average velocity formula:

$\overline{v}=\frac{y_{f}-y_{0}}{t_{f}-t_{0}}$

From this point on, you have two possibilities, either you find each individual $y_{f}, y_{0}, t_{f}, t_{0}$ and input them into the formula, or you find a formula you can use to directly input the change of times. I'll take the second approach.

We know that:

$t_{f}-t_{0}=\Delta t$

and we also know that:

$t_{f}=t_{0}+\Delta t$

in order to find the final position, we can substitute this final time into the function, so we get:

$y_{f}=29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}$

so we can rewrite our formula as:

$\overline{v}=\frac{29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}-y_{0}}{\Delta t}$

$y_{0}$ will always be the same, so we can start by calculating that, we take the provided function ans evaluate it for t=1s, so we get:

$y_{0}=29t-22t^{2}$

$y_{0}=29(1)-22(1)^{2}$

$y_{0}=7ft$

we can substitute it into our average velocity equation:

$\overline{v}=\frac{29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}-7}{\Delta t}$

and we also know that the initil time will always be 1, so we can substitute it as well.

$\overline{v}=\frac{29(1+\Delta t)-22(1+\Delta t)^{2}-7}{\Delta t}$

so we can now simplify our formula by expanding the numerator:

$\overline{v}=\frac{29+29\Delta t-22(1+2\Delta t+\Delta t^{2})-7}{\Delta t}$

$\overline{v}=\frac{29+29\Delta t-22-44\Delta t-22\Delta t^{2}-7}{\Delta t}$

we can now simplify this to:

$\overline{v}=\frac{-15\Delta t-22\Delta t^{2}}{\Delta t}$

Now we can factor Δt to get:

$\overline{v}=\frac{\Delta t(-15-22\Delta t)}{\Delta t}$

and simplify

$\overline{v}=-15-22\Delta t$

Which is the equation that will represent the average speed of the ball. So now we can substitute each period into our equation so we get:

$\overline{v}_{@\Delta t=0.01s}=-15-22(0.01)=-15.22ft/s$

$\overline{v}_{@\Delta t=0.005s}=-15-22(0.005)=-15.11ft/s$

$\overline{v}_{@\Delta t=0.002s}=-15-22(0.002)=-15.044ft/s$

$\overline{v}_{@\Delta t=0.001s}=-15-22(0.001)=-15.022ft/s$

5 0

3 years ago

What is the approximate radius of a sphere with a volume of 1436cm to power of 3

Margarita [4]

Answer:

<h3>The radius is 7 cm</h3>

Step-by-step explanation:

Volume of a sphere is given by

$V = \frac{4}{3} \pi {r}^{3}$

where r is the radius

From the question V = 1436 cm³

$1436 = \frac{4}{3} \pi {r}^{3}$

Multiply through by 3

We have

$4308 = 4\pi {r}^{3}$

Divide both sides by 4π

${r}^{3} = \frac{4308}{4\pi}$

${r}^{ 3} = \frac{1077}{\pi}$

Find the cube root of both sides

$r = \sqrt[3]{ \frac{1077}{\pi} }$

r = 6.99

We have the final answer as

Hope this helps

3 0

3 years ago

Can Someone Help M Plz

diamong [38]

The speed of the boat will be 10 mph in still water

4 0

2 years ago