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2 years ago

Please help me on these ones lol

Mathematics

1 answer:

TEA [102]2 years ago

5 0

3)
f(x) =(x+1)/4
so
f(6a) = (6a+1) / 4
f(6a) =3/2(a) + 1/4

8)
f(x) =(x+1)/4 = 0
x + 1 =0
x = -1

answer
x = -1 makes f(x) = 0

9)
(x+1)/4 >= 10
x + 1 >= 40
x >= 39

Answer
Domain is any number greater or equal 39 (x >= 39)

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BRAINLIEST AND 30 POINTS FOR WHOEVER CAN EXPLAIN HOW TO GET THESE ANSWERS...

Dvinal [7]

Step-by-step explanation:

Since m∠ACM = 90°, then by angle addition, m∠ACP + m∠PCM = 90°.
Since CP⊥ AM, then by definition of perpendicular, m∠APC = 90°. Since angles of a triangle add up to 180°, that means m∠PAC + m∠ACP = 90°.
By substitution, m∠PCM = m∠PAC.
Since m∠PCM + m∠CMP = 90°, then by substitution, m∠CMP = m∠PAC.
Therefore, by AAA, △ACP and △CMP are similar.

Having proven that the triangles are similar, we can write the proportion:

AP / CP = CP / MP

9 / CP = CP / 16

CP² = 144

CP = 12

Now, we can simply use Pythagorean theorem to find the other sides.

AC² = AP² + CP²

AC² = 9² + 12²

AC = 15

CM² = CP² + PM²

CM² = 12² + 16²

CM = 20

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2 years ago

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2 years ago

Simplify the expression: 2h+7+6+2h2

Alekssandra [29.7K]

2h2+2h+13 I believe!!!!

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2 years ago

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Solve x2 – 8x + 15 < 0. Select the critical points for the inequality shown.

quester [9]

Answer:

x=3,5

Explanation:

x2−8x+15=0

Try to express the terms of the equation in square form.

Adding 16 both sides of the equation,

(x2−2⋅x⋅4+42)+15=16

or,(x−4)2+15−16=0

or,(x−4)2−1=0

or,(x−4)2−12=0

This is the a2−b2=(a+b)(a−b)form.

(x−4+1)(x−4−1)=0

or,(x−3)(x−5)=0

Now, equate both the terms to zero since both of them when multiplied, give zero.

Either,

x−3=0

∴x=3

Or,

x−5=0

∴x=5

Ans:x=3,5 Hope this helpsXD...!!

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2 years ago

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Evaluate the integral. (Assume a ≠ b. Remember to use absolute values where appropriate. Use C for the constant of integration.)

Bess [88]

Answer:

F(x)= 5*[ $\frac{x^{3} }{3}$ + (a*b)* $\frac{x^{2} }{2}$ + a*b*x + C.

Step-by-step explanation:

First step we aplicate distributive property to the function.

5*(x+a)*(x+b)= 5*[ $x^{2}$ +x*b+a*x+a*b]

5*[ $x^{2}$ +x*(b+a)+a*b]= f(x), where a, b are constant and a≠b

integrating we find ⇒∫f(x)*dx= F(x) + C, where C= integration´s constant

∫^5*[ $x^{2}$ +x*(a+b)+a*b]*dx, apply integral´s property

5*[∫ $x^{2}$ dx+∫(a*b)*x*dx + ∫a*b*dx], resolving the integrals

5*[ $\frac{x^{3} }{3}$ + (a*b)* $\frac{x^{2} }{2}$ + a*b*x

Finally we can write the function F(x)

F(x)= 5*[ $\frac{x^{3} }{3}$ + (a*b)* $\frac{x^{2} }{2}$ + a*b*x ]+ C.

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