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inessss [21]
3 years ago
11

If a person puts 1 cent in a piggy bank on the first day, 2 cents on the second day, 3 cents on the third day, and so forth, how

much money will be in the bank after 40 days? $8.20 $16.40 $0.40 $4.10
Mathematics
1 answer:
cluponka [151]3 years ago
4 0
This is an arithmetic sequence with the common difference being 1

and if u have 1 cent on day 1 and 2 cents on day 2....then on day 40, u would have 40 cents....but we need the sum of all the days..

the sum of an arithmetic sequence can be found using the formula :
sn = n(a1 + an) / 2
n = number of terms = 40
a1 = first term = 1
an = last term = 40

now we sub
s(40) = 40(1 + 40) / 2
s(40) = 40(41)/2
s(40) = 1640/2
s(40) = 820.....820 cents = $ 8.20 <== the sum
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Step-by-step explanation:

The problem can be rewritten as follows: Find the sum of two consecutive entire numbers equal to 9. That is:

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3 years ago
Given f(x) = -x + 5, find f(-3).<br> Answer:
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Hey there!

<u>Find </u><u>f(</u><u>-</u><u>3</u><u>)</u><u> </u><u>:</u>

  • Answer :

f(-3) = 8 ✅

  • Explanation :

f(x) = -x + 5

<em>></em><em>></em><em> </em><em>Substitute </em><em>-</em><em>3</em><em> </em><em>for </em><em>x </em><em>in </em><em>f(</em><em>x)</em><em> </em><em>:</em><em> </em>

f(-3) = -(-3) + 5

f(-3) = 3 + 5

f(-3) = 8

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