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inessss [21]
3 years ago
11

If a person puts 1 cent in a piggy bank on the first day, 2 cents on the second day, 3 cents on the third day, and so forth, how

much money will be in the bank after 40 days? $8.20 $16.40 $0.40 $4.10
Mathematics
1 answer:
cluponka [151]3 years ago
4 0
This is an arithmetic sequence with the common difference being 1

and if u have 1 cent on day 1 and 2 cents on day 2....then on day 40, u would have 40 cents....but we need the sum of all the days..

the sum of an arithmetic sequence can be found using the formula :
sn = n(a1 + an) / 2
n = number of terms = 40
a1 = first term = 1
an = last term = 40

now we sub
s(40) = 40(1 + 40) / 2
s(40) = 40(41)/2
s(40) = 1640/2
s(40) = 820.....820 cents = $ 8.20 <== the sum
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andriy [413]

Answer:

Probability[(X - μ) < 1.1] = 0.6046

Step-by-step explanation:

Given:

σ² = 64

Mean μ = 34

Find:

Probability[(X - μ) < 1.1]

Computation:

Standard deviation σ = √σ²

Standard deviation σ = √64

Standard deviation σ = 8

Probability[(X - μ) < 1.1] = Probability[-1.1 < (X - μ) < 1.1]

Probability[(X - μ) < 1.1] = Probability[-1.1/(8/√38) < (X - μ) < 1.1/(8/√38)]

Using z table

Probability[(X - μ) < 1.1] = 0.6046

7 0
3 years ago
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REY [17]

Answer:

-2

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f(g(2)) = f(3) = 3^2 - 3*3 - 2

= 9-9-2

= -2

7 0
3 years ago
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victus00 [196]

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Goryan [66]

Answer:

Please see below :)

Step-by-step explanation:

The slope is just what's in front of the x!

So:

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Answer:

C and D

Step-by-step explanation:

I had this same problem on my quiz

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