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PolarNik [594]
2 years ago
13

4÷6.12= what is the answer?

Mathematics
1 answer:
Ede4ka [16]2 years ago
7 0

Answer:

0.65359477124. this is probably the wrong answer so I'm just gonna guess u needed the answer the other way around because it makes more sense so 6.12 ÷ 4 = 1.53.

Step-by-step explanation:

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For which of the following is the shape of the sampling distribution of the sample mean approximately normal? a random sample of
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Answer:

a random sample of size 5 from a population that is approximately normal

a random sample of size 60 from a population that is strongly skewed to the left.

Step-by-step explanation:

They are both correct

6 0
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Help please ((: ughhh
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4 0
3 years ago
Please help on two math questions. I don’t understand how to do them.
Sidana [21]

When you represent intervals on the number line, you're including full dots, excluding empty dots, and you're considering numbers highlighted by the line.

In the first case, you've highlighted everything before -2 (full dot, thus included), and everything after 1 (empty dot, excluded). So, the set would be

x\leq -2 \lor\ x>1

or, in interval notation,

(-\infty,-2]\cup (1,\infty)

In the second case, you are looking for all numbers between -3 and 5. This interval is symmetric with respect to 1: you're considering all numbers that are at most 4 units away from 1, both to the left and to the right.

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|x-1|\leq 4

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3 0
2 years ago
Maya has 120 caramel apples to sell. Each caramel apple is covered with one toppin.
EleoNora [17]

they got sold by her

Step-by-step explanation:

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5 0
3 years ago
A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th
OlgaM077 [116]

Answer:

Interval [16.34 , 21.43]

Step-by-step explanation:

First step. <u>Calculate the mean</u>

\bar X=\frac{(23+18+23+12+13+23)}{6}=18.666

Second step. <u>Calculate the standard deviation</u>

\sigma =\sqrt{\frac{(23-18.666)^2+(18-18.666)^2+(23-18.666)^2+(12-18.666)^2+(13-18.666)^2+(23-18.666)^2}{6}}

\sigma=\sqrt\frac{18.783+0.443+18.783+44.435+5.666+18.783}{6}

\sigma=\sqrt{17.815}=4.22

As the number of data is less than 30, we must use the t-table to find the interval of confidence.

We have 6 observations, our level of confidence DF is then 6-1=5 and we want our area A to be 80% (0.08).  

We must then choose t = 1.476 (see attachment)

Now, we use the formula that gives us the end points of the required interval

\bar X \pm t\frac{\sigma}{\sqrt n}

where n is the number of observations.

The extremes of the interval are then, rounded to the nearest hundreth, 16.34 and 21.43

6 0
3 years ago
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