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I am Lyosha [343]
3 years ago
14

23.6-2×3÷2 what is the answer to this question

Mathematics
1 answer:
lys-0071 [83]3 years ago
8 0

Answer:

20. 3

Step-by-step explanation:

23.6 - 2 × 3 ÷ 2 = 23.6 - 3

                         = 20.3

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Find the LCM of the numbers using prime factorizations. 36,60
alexandr402 [8]
36=2*2*3*3=2²*3²
60=2*2*3*5=2²*3*5

LCM(36,60)=2*2*3*3*5=2²*3²*5=180
5 0
3 years ago
Jaclyn started the week with $284.28 in her checking
Mashcka [7]

Answer:

$165.62

Step-by-step explanation:

284.28-40-48.39-30.27=165.62

5 0
3 years ago
Read 2 more answers
PLZ SOLVE PIC ATTACHED BELOW
ludmilkaskok [199]

Answer:

\tan(51°)  =  \frac{10}{x}  \\x =  \frac{10}{ \tan(51°) }  \\ x = \frac{10}{1.235}  \\ \boxed{ x = 8.1}

<h3>★ Value of x is <u>8.1</u>.</h3>

\sin(51°)=  \frac{10}{H}  \\ h =  \frac{10}{ \sin(51°) }  \\ H=  \frac{10}{0.777}  \\  \boxed{H= 12.8676}

<h3>★ Value of H is <u>12.8676</u>.</h3>

Remember:

  • tan∅=Perpendicular/Base
  • sin∅=Perpendicular/Hypotenuse

4 0
3 years ago
A cube measures 3.0 CM on each side and has a mass of 25g. What is the density?
Oxana [17]

Answer:

D ≈ 0.925926 g/cm³

Step-by-step explanation:

Density = Mass / Volume

Step 1: Define

M = 25 g

V = (3 cm)³ = 27 cm³

D = ?

Step 2: Substitute and Evaluate for Density

D = 25g / 27 cm³

D = 25/27 g/cm³

D ≈ 0.925926 g/cm³

8 0
3 years ago
A dog owner wants to use 200 ft of fencing to enclose the greatest possible area for his dog. he wants the fenced area to be rec
Fiesta28 [93]
Perimeter (P) = 2 · Length(L) + 2 · Width (W) → P = 2L + 2W
Solve for either L or W (I am solving for L).
200 - 2W = 2L
(200 - 2W)/2 = L
100 - W = L

Area (A) = Length (L) · Width (W)
              = (100 - W) · W
              = 100W - W²

Find the derivative, set it equal to 0, and solve:
dA/dW = 100 - 2W
     0    = 100 - 2W
     W  = 50

refer to the equation above for L: 
100 - W = L
100 - 50 = L
        50  = L

Dimensions for the maximum Area are 50 ft x 50 ft
5 0
3 years ago
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