Question

Write in equation of the line containing the points (-8,-8) and (-9,-10

Answer 1

Answer:

y = 2x + 8

Step-by-step explanation:

Find the slope of a line between (-8,-8) and (-9,-10) using m = $\frac{y_2-y_1}{x_2-x_1}$, which is the change in y over the change in x.

Substitute in the values of x and y into the equation to find slope.

$m= \frac{-10-(-8)}{-9(-8)}$

Simplify.

Simplify the numerator.

Multiply -1 by -8

$m=\frac{-10+8}{-9-(-8)}$

Add -10 and 8

$m=\frac{-2}{-9-(-8)}$

Simplify the denominator.

Multiply -1 by -8

$m=\frac{-2}{-9+8}$

Add -9 and 8.

$m=\frac{-2}{-1}$

Divide -2 by -1.

$m=2$

Using the point slope form $y-y_1=m(x-x_1)$ plug in m = 2, $x_1 = -8, y_1 = -8$

$y-(-8)=(2)(x-(-8))$

Solve for y.

Multiply -1 by -8

y + 8 = ( 2 ) ( x − ( − 8 ) )

Simplify  ( 2 ) ( x − ( − 8 ) ) .

Multiply  − 1  by  − 8

y+8 = 2 ( x + 8 )

Apply the distributive property.

y + 8 = 2 x + 2 ⋅ 8

Multiply  2  by  8 .

y + 8 = 2x + 16

Move all terms not containing  y  to the right side of the equation.

Subtract  8  from both sides of the equation.

y = 2 x + 16 − 8

Subtract  8  from  16 .

y = 2 x + 8