Answer:
D) The lac operon will function normally.
Explanation:
- The promoter area can be described as the area that causes the transcription to initiate for a particular gene. Promoters may be near the genes from which they initiate transcription or they may display multiple scenes upstream.
- The lock operon works normally because the promoter area can still enable transcription on many base pairs. Detects repression promoter and works normally.
- so correct option is D) The lac operon will function normally.
Answer:
The correct answer is - 6.8950.61 gm per mole
Explanation:
Given:
One form of hemoglobin is 0.324% Fe by mass
1 hemoglobin = 4 Fe
Solution:
Molar Mass of iron = 55.85
mass of 4 iron atom = 55.85 * 4 = 223.4 gms
0.324 % correspond to 223.4 gms
100 % correspond to = 223.4 *100/0.324
= 68950.61 gm
MM of haemoglobin = 68950.61 gms = 6.8 E4 gms
Answer: There will be no effect on the protein produced
Explanation:
According to the genetic code, the triplet codon GAG code for the amino acid, glutamate, while GAC code for aspartate.
Since GAG and GAC code for amino acids with similar properties (aspartate and glutamate are both acidic amino acids due to the extra carboxyl group present in their side chain), the change in nucleotide is still similar to the original, so will result in a different amino acid sequence, but will not alter the function of the protein at all. Thus, this kind of mutation is called silent mutation.