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sergeinik [125]
3 years ago
11

In Microsoft word when you highlight existing text you want to replace you are in what mode

Computers and Technology
1 answer:
algol [13]3 years ago
7 0
Find and replace mode
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Write a program that creates a list (STL list) of 100 random int values. Use the iterators to display all the values of the list
sertanlavr [38]

Answer:

The program is as follows:

#include <bits/stdc++.h>

#include <iostream>

using namespace std;

int main(){

  list <int> myList;

  for(int i=0;i<100;i++){  

      myList.push_back(rand()%100);       }

   list <int> :: iterator it;

   cout<<"Forward: ";

   for(it = myList.begin(); it != myList.end(); ++it){

       cout <<*it<<" ";    }

   

   cout<<"\nReversed: ";

   std::copy(myList.rbegin(),myList.rend(),std::ostream_iterator<int>(std::cout, " "));

        myList.sort();  

   cout<<"\nSorted: ";

   for(it = myList.begin(); it != myList.end(); ++it){

       cout <<*it<<" ";    }

   return 0;

}

Explanation:

This declares the list

  list <int> myList;

The following iteration generates 100 random integers into the list

<em>   for(int i=0;i<100;i++){  </em>

<em>       myList.push_back(rand()%100);       } </em>

This initializes an iterator

   list <int> :: iterator it;

This prints the header "Forward"

   cout<<"Forward: ";

This iterates through the list and prints it in order

<em>    for(it = myList.begin(); it != myList.end(); ++it){ </em>

<em>        cout <<*it<<" ";    } </em>

    This prints the header "Reversed"

   cout<<"\nReversed: ";

This uses ostream_iterator to print the reversed list

   std::copy(myList.rbegin(),myList.rend(),std::ostream_iterator<int>(std::cout, " "));

This sorts the list in ascending order

        myList.sort();

This prints the header "Reversed"  

   cout<<"\nSorted: ";

This iterates through the sorted list and prints it in order

   for(it = myList.begin(); it != myList.end(); ++it){

       cout <<*it<<" ";    }

4 0
3 years ago
Your bank contacts you to phone a number supplied in the email. What do you do?
never [62]
Login thru a secure portal and verify messages and then report any issues. also another thing you may call your bank to make sure they are the ones who sent the email.
5 0
3 years ago
Steeler corporation is planning to sell 100,000 units for 2.00 per unit and will break even at this level of sales fixed expense
olga_2 [115]

Answer:

1.25 per unit

Explanation:

Number of units to sell = 100,000

Price per unit = 2

Fixed expense = 75000

At break even point :

Revenue = total expenses

Total expenses = fixed cost + variable cost

Let variable cost = x

Revenue = units to sell * price per unit

Revenue = 100,000 * 2 = 200,000

Hence,

Fixed cost + variable cost = Revenue

75000 + x = 200,000

x = 200, 000 - 75000

x = 125,000

Variable cost = 125,000

The variable expense per unit is thus :

Variable expense / number of units

125,000 / 100,000 = 1.25 per unit

7 0
3 years ago
The three activities in an information system that produce the information organizations use to control operations are: 1. infor
forsale [732]

Answer:

5. Input, Processing, and Output

Explanation:

Input, processing, and output are the three activities in an information system that produce the information an organisation needs.

<em>Input</em> captures or collects raw data from within the organisation or from its external environment.

<em>Processing</em> converts this raw input into a meaningful form.

<em>Output</em> transfers the processed information to the people who will use it or to the activities for which it will be used. Information systems also require feedback, which is output that is returned to appropriate members of the organisation to help them evaluate or correct the input stage.

7 0
3 years ago
What is the largest decimal value you can represent, using a 86-bit signed<br> integer?
Nataly [62]

Answer:

2^{85}-1

Explanation:

Considering the number are stored using binary notations.

If there are total 86 bits and 1 bit is used as sign bit. Then in total one can have 2^{85} bit combinations since a bit can be either stored as 0 or as 1.

Therefore,  the largest number that can be stored will be 2^{85}-1.

To understand it in better way let's scale down the problem to 3 bits representation. The largest number that can be stored using 3 bits is 111 which in decimal form is 7 and is equal to 2^{3}-1.

4 0
3 years ago
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