5x+3y=-6 ...(1)
2x-3y=27 ...(2)
We can add equations (1) and (2) to eliminate y . So,
7x+0=21
7x=21
Divide each sides by 21 to isolate x.
So, x= 3
Now plug in x=3 in equation (1) to get the value of y.
So, 5(3)+3y=-6
15 +3y= -6
15+3y-15=-6-15
3y= -21
![\frac{3y}{3} =\frac{-21}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3y%7D%7B3%7D%20%3D%5Cfrac%7B-21%7D%7B3%7D%20%20)
So, y=-7.
Hence, x=3 and y=7.
Answer:
y=6x-8
Step-by-step explanation:
Answer:
This value of x will make equation true
Step-by-step explanation:
Given as ;
3x -
= 7x - ![\frac{3}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B6%7D)
I,.e
-
= 7x - 3x
Or,
= 4 x
∴ x=
Hence this value of x will make equation true Answer
Since < ABD is a right triangle (with a measure of 90 °), we can establish the formula to solve for the value of x:
Let < BAC = m < 1 = (15x - 2)°
< CAD = m < 2 = (7x + 4)°
Use the formula:
m < 1 + m < 2 = 90°
Substitute the values of m < 1 and 2:
15x - 2 + 7x + 4 = 90°
Combine like terms:
22x + 2 = 90°
Subtract 2 from both sides:
22x + 2 - 2 = 90° - 2
22x = 88°
Divide both sides by 22:
22x/22 = 88/22
x = 4
Now that we have the value of x, we can plug this value into the given angles:
< BAC = m < 1 = (15x - 2)° = 15(4) - 2 = 58°
< CAD = m < 2 = (7x + 4)° = 7(4) + 4 = 32°
m < 1 + m < 2 = 90°
58° + 32° = 90°
90° = 90° (true statement).
Therefore, (15x - 2)° = 58° and (7x + 4)° = 32°.
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