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solniwko [45]
3 years ago
5

Arlen buys 2 small cups of food for the animals for 5 tokens.Explain how to use a diagram to find how many cups of food Arlen co

uld buy for 20 tokens.
Mathematics
1 answer:
Hatshy [7]3 years ago
5 0
5 divided by 20 equals 4 - 2 =2
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lbvjy [14]

Answer:55

Step-by-step explanation:

55

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3 years ago
What is the value of 10×+z=150<br>​
JulijaS [17]

Answer:

<h2><u><em>15</em></u></h2>

Step-by-step explanation:

what is the value of 10×+z=150

10× (+z) = 150

10 × z = 150

z = 150 : 10

z = 15

-----------------------

check

10 × 15 = 150

the answer is good

8 0
2 years ago
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Evaluate the following integrals: 1. Z x 4 ln x dx 2. Z arcsin y dy 3. Z e −θ cos(3θ) dθ 4. Z 1 0 x 3 √ 4 + x 2 dx 5. Z π/8 0 co
Zigmanuir [339]

Answer:

The integrals was calculated.

Step-by-step explanation:

We calculate integrals, and we get:

1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}

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3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}

4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}

5)  \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=

=\frac{3π+8}{64}

6)  ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x

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8)  ∫ tan^5 (x) sec(x)  dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x

6 0
3 years ago
What is the surface area of the prism?
kow [346]
The\ surface\ area:A_s=2B+(S_1+S_2+S_3)\cdot H\\B=\frac{12\cdot5}{2}=\frac{60}{2}=\boxed{30\ (yd^2)}\\\\S_1=5yd;\ S_2=12yd;\ S_3=13yd;\ h=8yd\\\\therefore\\\\A_s=2\cdot30+(5+12+13)\cdot8=60+30\cdot8=60+240=\boxed{300\ (yd^2)}Volume\ of\ the\ prism:V=B\cdot H\\\\B\ (base)\ it's\ a\ right\ triangle:B=\frac{12\cdot5}{2}=\frac{60}{2}=\boxed{30\ (yd^2)}\\\\H=8yd\\\\therefore\\\\V=30\cdot8=\boxed{240\ (yd^2)}\leftarrow\boxed{C}
8 0
3 years ago
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Which one is greater <br> 0.09 or 0.091
dedylja [7]

Answer:

0.091

Step-by-step explanation:

fill in and make them both thousandths.0.090 and 0.091The second one is larger. 0.091

6 0
3 years ago
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