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tia_tia [17]
3 years ago
6

The table shows a student’s results from spinning the pointer 30 times. Find the experimental probability that the pointer lands

in a section with a number greater than or equal to 3.
Mathematics
1 answer:
professor190 [17]3 years ago
7 0
50 I don’t really know
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Write and solve the equation: Bill spent $23 on 4 drinks at $2 each and some hotdogs at $3 each.
Phantasy [73]

Answer:

5 hotdogs

Step-by-step explanation:

23 (4 drinks and some hotdogs )

hotdogs is $3 each

drinks is $2 each

$2×4 drink=$8

$23-$8=$15

$15÷3=5

8 0
3 years ago
Read 2 more answers
The function y = -3(x - 4) 2+ 2 shows the daily profit (in hundreds of dollars) of a taco food truck, where x is the price of a
Paha777 [63]
Y = .05
x = 4.3 repeating
6 0
3 years ago
Write the expression in expanded notation for (-3 power of 5)
Murljashka [212]

Step-by-step explanation:

A. Base = <em><u>(-3)</u></em>

B. Exponent = <em><u>5</u></em>

C. (-3)^5

= <em><u>(-3) × (-3) × (-3) × (-3) × (-3) (In expanded notation form)</u></em>

D. Evaluation of equation will be = <em><u>-243</u></em>

4 0
3 years ago
Parallelogram MNPQ has vertices at M(5,14), N(10,16), P(12,11), Q(7,9). Just using the Diagonals,
Julli [10]

Answer:

square

Step-by-step explanation:

You use the Pitagora's theorem to calculate the diagonals of the figure.

The diagonals are given by the distance NQ and MP.

By calculating the value of these diagonals you have:

d_{NQ}=\sqrt{(10-7)^2+(16-9)^2}=\sqrt{58}\\\\d_{MP}=\sqrt{(12-5)^2+(11-14)^2}=\sqrt{58}

These diagonlas are equal between them. Hence, the figure is a square

6 0
4 years ago
Use the Factor Theorem to find ALL zeros of f(x) = x^3 - x^2 - 11x + 15, given that 3 is a zero. Show all work and express zeros
ELEN [110]

Answer:

Step-by-step explanation:

by synthetic division

3) 1   -1   -11    15

|       3     6   -15   (add)

____________

   1     2    -5 |0

x²+2x-5=0

x=\frac{-2 \pm\sqrt{2^{2} -4*1*-5} }{2*1} \\or~x=\frac{-2 \pm\sqrt{4+20} }{2} \\or~x=\frac{-2 \pm2\sqrt{6} }{2} \\or ~x=-1 \pm \sqrt{6}

5 0
3 years ago
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