Factor 1/6 out of 1 /6 x + 29/ 6

Please help!! If y = sin x, then dy/dx =

Citrus2011 [14]

Answer:

the answer is option B

Step-by-step explanation:

To find dy/dx the equation here is

first multipled by derivative of second + second multipled by derivative of first

y = x*sinx

dy/dx = x * derivative of sinx + sinx * derivative of x

derivative of x with respect to x is 1

derivative of sinx with respect to x is cosx

therefore

dy/dx = x * cosx + sinx * 1

= x * cosx + sinx

5 0

3 years ago

g In a certain rural county, a public health researcher spoke with 111 residents 65-years or older, and 28 of them had obtained

Marat540 [252]

Answer:

95% confidence interval for the percent of the 65-plus population that were getting the flu shot is [0.169 , 0.331].

Step-by-step explanation:

We are given that in a certain rural county, a public health researcher spoke with 111 residents 65-years or older, and 28 of them had obtained a flu shot.

Firstly, the Pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of residents 65-years or older who had obtained a flu shot = $\frac{28}{111}$ = 0.25

n = sample of residents 65-years or older = 111

p = population proportion of residents who were getting the flu shot

Here for constructing 95% confidence interval we have used One-sample z test for proportions.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.25-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } }$ , $0.25+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } }$ ]

= [0.169 , 0.331]

Therefore, 95% confidence interval for the percent of the 65-plus population that were getting the flu shot is [0.169 , 0.331].

7 0

3 years ago

Write an exponential function to model the following situation

Dominik [7]

Answer:

$y = 140000(1.04)^{x}$ ; 262 000

Step-by-step explanation:

The general formula for an exponential function is

$y = a(b)^{x}$

a = 140 000; b = 1.04; x = 16

$y = 140000(1.04)^{x}$

y = 140 000(1.04)¹⁶

y = 140 000 × 1.873

y = 262 000

The graph below shows the population growth over time.

7 0

3 years ago

Help me please someone. Im giving brainliest!!

rodikova [14]

Answer:

19

Step-by-step explanation:

114 divided by 6

7 0

3 years ago

Read 2 more answers

The graph below shows a household’s budget. If the household spends $2,000 a month, which of the following statements is not tru

andreev551 [17]

The THIRD statement is not true.
$2000 (spends a month)
The 5% of $2000 is only $100 for food.

The first statement is true "The household spend $260 per month on the car".
13 % of $2000 = $260

The second statement is true "The household spend $600 per month for rent".
30% of $2000 = $600

The fourth statement is also true "The household spend $200 in savings each month"
10% of $2000 = $200

3 0

3 years ago