Sent a picture of the solution to the problem (s). I usually graph at least 5 points. Usually one is 0 and I go up from zero and down from zero.
Jerry can complete a sales route by himself in 5 hours. Working with an associate, he can complete a sales route in 3 hours. Ho
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Complete the square for x and y.
7x^2 + 3y^2 - 28x - 12y = -19
7x^2 - 28x + 3y^2 - 12y = -19
7(x^2 - 4x) + 3(y^2 - 4y) = -19
7(x^2 - 4x + 4) + 3(y^2 - 4y + 4) = -19 + 28 + 12
7(x - 2)^2 + 3(y - 2)^2 = 21
7x^2 + 3y^2 - 28x - 12y = -19
7x^2 - 28x + 3y^2 - 12y = -19
7(x^2 - 4x) + 3(y^2 - 4y) = -19
7(x^2 - 4x + 4) + 3(y^2 - 4y + 4) = -19 + 28 + 12
7(x - 2)^2 + 3(y - 2)^2 = 21
Answer:
<h2> y = 0.25x + 2</h2>Step-by-step explanation:
(0, 2) ⇒ x₁ = 0, y₁ = 2
(-4, 1) ⇒ x₂ = -4, y₂ = 1
So the slope:
The point-slope form of the equation of the line passing through point (x₀,y₀) and with slope m is: y - y₀ = m(x - x₀)
m = 0.25
(0, 2) ⇒ x₀ = 0, y₀ = 2
Therefore:
y - 2 = 0.25(x - 0)
y - 2 = 0.25x {add 2 to both sides}
y = 0.5x + 2 ← the slope-intercept form of the equation