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4 years ago

A = h/2 * (a + b ); for h

Mathematics

2 answers:

Ksivusya [100]4 years ago

7 0

h/2 * (a + b )=A
h/2=A/(a+b)
h=2A/(a+b)

vova2212 [387]4 years ago

4 0

$A=\dfrac{h}{2}(a+b)\\
2A=h(a+b)\\
h=\dfrac{2A}{a+b}
$

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The value (in cents) of the change in a purse that contains twice as many nickels as pennies, five more dimes than nickels, and

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Value of the pursue in cents: $131p+175$

Step-by-step explanation:

Let's call:

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The problem tells us that the pursue contains twice as many nickels as pennies, so the number of nickels is

$n=2p$

Also, the pursue contains five more dimes than nickels, so the number of dimes is

$d=n+5=2p+5$

And finally, the pursue contains as many quarters as dimes and nickels combained, so the number of quarters is

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The value of each type of coin is:

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Nickel: 5 cents

Dime: 10 cents

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So, the total value of the pursue in cents is:

$1p+5n+10d+25q$

And substituting,

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So, this is the value of the change in the pursue in cents.

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4 years ago

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Hello! :)

Answer:

$\boxed{X=11}$

*The answer must have a POSITIVE sign!*

Step-by-step explanation:

Expand with distributive property: a(b+c)=ab+ac

4*5=20

6*4=24

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2*8=16

2*10=20

16x+20

20x-24=16x+20

First, you add by 24 both sides of an equation.

20x-24+24=16x+20+24

20x=16x+44

You subtract by 16x both sides of an equation.

20x-16x=16x+44-16x

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Then, you divide by 4 both sides of an equation.

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Divide by the numbers from left to right.

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X=11 is the final answer

Hope this helps!

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