He will of paid £420 as intrest
Answer:
Yes
Step-by-step explanation:
Yes this a function.
It's a quadratic function, a parabola.
Because it also does passes the vertical line test, it is a function.
Anything that passes a vertical line test, it's a function!
Hope this helps!
21. 5(16v^2 -25)
5(4v + 5)(4v-5)
22. (3y + 5)(3y-5)
23. (3m - 1)^2
24. 4(9n^2 - 12n + 4)
4(3n - 2)^2
25. Doesn't look like there's much to factor... 3(3k^2 - 10k)
26. (n - 9)(n - 8)
27. (3a - 8)(a + 7)
28. 5(7r+5)(r+3)
Given the basis β={(1,−1,3),(−3,4,9),(2,−2,4)}β={(1,−1,3),(−3,4,9),(2,−2,4)} and x=(8,−9,6)x=(8,−9,6), I am to find the corresponding coordinate vector [x]β[x]β. I claim that the coordinate vectors entries x1,x2,x3x1,x2,x3 meet the following criterion:
x1(1,−1,3)+x2(−3,4,9)+x3(2,−2,4)=(8,−9,6)x1(1,−1,3)+x2(−3,4,9)+x3(2,−2,4)=(8,−9,6)This is equivalent to solving the augmented matrix
⎡⎣⎢1−13−3492−248−96⎤⎦⎥[1−328−14−2−93946]which is row equivalent to
⎡⎣⎢100−31020−18−10⎤⎦⎥
-12
4=-8-x
Add 8 to each side
12=-x
Divide both side by -1
-12=x
