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2 years ago

Please answer fast, I need it

Mathematics

1 answer:

Citrus2011 [14]2 years ago

3 0

180 degrees because both angles are on the same side of transversal so they have to add up to 180

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Divide the following fractions 1/4÷1/2

artcher [175]

1/4 / 1/2 =
1/4 x 2/1 = 2/4 = 1/2

7 0

2 years ago

Business/multivariable calc question help needed asap!!!!

UkoKoshka [18]

Answer:

There is a  min  value of  800  located at (x,y) =  (16, 12) 

==========================================================

Explanation:

Let's solve the second equation for y

4x+3y = 100

3y = 100-4x

y = (100-4x)/3

We'll plug that into the first equation

f(x,y) = 2x^2+2y^2

g(x) = 2x^2+2((100-4x)/3)^2

g(x) = 2x^2+(2/9)*(100-4x)^2

g(x) = 2x^2+(2/9)*(10,000-800x+16x^2)

This graphs a parabola that opens upward, due to the positive leading coefficient. This g(x) curve has its vertex point at the minimum.

Apply the derivative to help find the minimum

g(x) = 2x^2+(2/9)*(10,000-800x+16x^2)

g ' (x) = 4x+(2/9)*(-800+32x)

------------------------

Set the derivative function equal to 0 and solve for x

g ' (x) = 0

4x+(2/9)*(-800+32x) = 0

4x+(2/9)*(-800)+(2/9)*(32x) = 0

4x-1600/9+(64/9)x = 0

9(4x-1600/9+(64/9)x) = 9*0

36x-1600+64x = 0

100x-1600 = 0

100x = 1600

x = 1600/100

x = 16

Use this x value to find y

y = (100-4x)/3

y = (100-4*16)/3

y = (100-64)/3

y = 36/3

y = 12

-----------------------

Therefore, (x,y) = (16,12) leads to the largest value of f(x,y) = 2x^2+2y^2

That smallest f(x,y) value is...

f(x,y) = 2x^2+2y^2

f(16,12) = 2*16^2+2*12^2

f(16,12) = 800

8 0

2 years ago

Please help?!

Anton [14]

Answer:

Δ PQT ~ Δ QRS .....{S-S-S test for similarity}...Proof is below.

Step-by-step explanation:

Given:

In Δ PQT

PQ = 30 ft

QT = 28 ft

TP = 20 ft

In Δ QRS

QR = 15 ft

RS = 14 ft

SQ = 10 ft

To Prove:

Δ PQT ~ Δ QRS

Proof:

First we consider the ratio of the sides

$\frac{PQ}{QR}=\frac{30}{15} = \frac{2}{1}$ ..............( 1 )

$\frac{QT}{RS}=\frac{28}{14} = \frac{2}{1}$ ..............( 2 )

$\frac{TP}{SQ}=\frac{20}{10} = \frac{2}{1}$ ..............( 3 )

So By equation ( 1 ), ( 2 ) and ( 3 ) we get

$\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}$

Now in Δ PQT and Δ QRS we have

$\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}$

Which are corresponding sides of a similar triangle in proportion.

∴ Δ PQT ~ Δ QRS .....{S-S-S test for similarity}...Proved

8 0

2 years ago

True or False, the following numbers are in order from greatest to least: 11/10, 8/7,-2.34*

rjkz [21]

Answer:

fasle

Step-by-step explanation:

6 0

3 years ago

YOOO PLEASE HELPPPP!!!!

Evgesh-ka [11]

Given:

Base length of triangle = 40 units

Height of triangle = 9 units

Length of hypotenuse of triangle = 41 units

To find:

Find the value of Tan A

Steps:

Tan of an angle is equal to the opposite length by adjacent length.

So,

Tan A = $\frac{opposite}{adjacent}$

Tan A = $\frac{9}{40}$

Tan A = 0.225

Therefore, the exact value of Tan A is 0.225.

Happy to help :)

If you need any help, feel free to ask

4 0

2 years ago