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stira [4]
4 years ago
6

PLEASE HELP ME WITH THIS

Mathematics
1 answer:
Harrizon [31]4 years ago
6 0

Answer:

The last option.

Step-by-step explanation:

Hope this helps!

Wait hold on

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Segment AB is bisected by point M. Segment AM is 5 units. Find the length of segment AB.
laila [671]

Answer:

Segment AB is 10 units long.

Step-by-step explanation:

When a segment is bisected, it is divided into two segments of equivalent lengths.  Because segment AB is bisected by point M it creates a line somewhat like this.

A --------------------M----------------------B

Thus, if segment Am is 5 units, because segment AM is congruent to BM, segment BM is 5 units as well.  Thus, because AM + BM = AB, AB = 10 units.

7 0
3 years ago
19. You decide to sell your ipod. You initially paid $300 for it. It has been 2 years and each year the value depreciated
Paul [167]

Answer:

$90

Step-by-step explanation:

300×0.70=210

300-210=90

3 0
3 years ago
Which expressions are equivalent to 16^x/4^x
Mashcka [7]
16^1 = 4^2 16•1 = 4•4 16 = 16
3 0
4 years ago
Which sum or difference identity would you use to verify that cos (180° - ∅) = -cos ∅?
Tom [10]

Answer: Option C is correct


Step-by-step explanation:

We know tha tCos(A-B) = cosA cosB + sinAsinB

Plugging A = 180 and B = Ф

cos(180-Ф)= cos180cosФ+sin180sinФ

                  = (-1) cosФ+ (0) sinФ   [ since cos180=-1 and sin180 =0]

                 = -cosФ + 0

                 = -cosФ

Therefore option C is the correct answer.        

6 0
3 years ago
Read 2 more answers
22, 23, 23, 24, 20, 8<br> What is the most appropriate measure of center?
blondinia [14]

Answer:

In this data set, the <u>number 8 is an outlier. </u>

<u> An outlier is a value that is far away from the rest of the numbers </u>(either a lot smaller or a lot greater).

Because there is an outlier, the measure of center that best represents the data would be the <u>median (the middle value)</u>.

<u> The mean will not be accurate because the outlier will make it smaller than what is actually being represented in all of the numbers but one.</u>

Hope this helps!!!!

6 0
4 years ago
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