If $200 is the maximum a coach can spend on new shorts, and needs at least 15 shorts, then you could divide or use an inequality. first take the maximum number (200) and the minimum amount (15s) and use the minimum and maximum signs of knowledge to form an inequality. you should end up with 15s<200.
Answer:
-3 + (n-1)(-4)
Step-by-step explanation:
We follow the formula.
a1 + (n-1)d
d is the common difference.
Answer:
6 socks
Step-by-step explanation:
What we must do is calculate the probability of this happening, that he takes out two black socks in the first two taken out.
There are 12 black socks and in total they are 24, therefore the probability of drawing 1 is:
12/24
and now the probability of getting another one is 11 (there is one less outside) and in total they are 23:
11/23
the final probability is the multiplication of these events:
(12/24) * (11/23)
P = 0.24
Now, to know how many you should get, we multiply the probability by the total number of socks, that is:
0.24 * 24 = 5.76
So you must take out at least 6 socks for the above to happen.
Let x = hours to meet
train one has a 2 hour head start or 210 km head start
210 + 105x = 135x
30x = 210
x = 7 hours to meet
C. You would first have to divide A by Pi, then take the square root of r, in order to get r by itself.
