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3 years ago

How do you write 550% as a fraction, mixed number, or whole number in simplest form? submit?

1 answer:

5 0

550% = 5 1/2 = 5.5 = 55/10

fraction: 55/10 = 11/2
Mixed number: 5 1/2
I'm not exactly sure what a whole number in its simplest form is, but it should be one of those answers above.

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Mr. Brown shares with the class that 70% of the students got an A on the English vocabulary quiz. If Mr. Brown has 100 students,

mezya [45]

Answer:

a. $\frac{70}{100}$

b. 0.7

c. 0.7=70%= $\frac{70}{100}$

Step-by-step explanation:

70% of 100 received an A, that is 70/100 times 100 equal to 70

$\frac{70}{100}*100=70$

a. 70% = $\frac{70}{100}$

b. $\frac{70}{100}$ = 0.7

Notice that 70/100 is equal to 7/10 which is 0.7

c. 0.7=70%= $\frac{70}{100}$

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3 years ago

What is the difference of 15 and 7?<br> O<br> 3<br> Sondrit<br> Not

viva [34]

Answer:

Step-by-step explanation:

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3 years ago

The amount of garbage, G produced by a city with population p is given by G = f(p). G is measured in tons per week, and p is mea

barxatty [35]

Alright, so this is simple.

P= 50,000 or 50 thousands

G= 13 Tons

The variable f isn't known.

So your equation would be 13 = 50 (f), if you were to put your known variables in the equation.

If you were to find variable f, you would divide 13 tons by 50,000 to get 0.00026 or in scientific notation: 2.6 x 10 (exponent(s):-4)

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3 years ago

A group of astronomers observed light coming from a star located a distance of 331,000,000,000,000,000,000,000,000 light-years f

Anika [276]

3.31 times 10 to the 26th power

5 0

3 years ago

Read 2 more answers

Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0

Debora [2.8K]

So, the definite integral $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Given that

$\int\limits^1_0 {x^{2} } \, dx = 13$

We find

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx$

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, $Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6\int\limits^1_0 {x^{2} } \, dx$

Since

$\int\limits^1_0 {x^{2} } \, dx = 13$ ,

Substituting this into the equation the equation, we have

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx = 4 - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6 X 13 \\= 4 - 78\\= -74$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Learn more about definite integrals here:

brainly.com/question/17074932

4 0

2 years ago