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3 years ago

5

What is the solution of 7<5-2x<17

1 answer:

Yakvenalex [24]3 years ago

5 0

Step Number 1. Subtract 5 from the whole equation.

$7-5\ \textless \ -2x\ \textless \ 17-5$

Step Number 2. Simplify

$2\ \textless \ -2x\ \textless \ 12$

Step Number 3. Divide the whole equation by -2

$-1\ \textgreater \ x\ \textgreater \ -\frac{12}{2}$

Step Number 4. Simplify

$-1\ \textgreater \ x\ \textgreater \ -6$

Done! :)

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During a sale at the mal, all items were marked down 40% off of the original price. Lily purchased a purse that was originall $2

NNADVOKAT [17]

Answer:

$132

Step-by-step explanation:

40% off means it is actually 60% of the regular price.

Thus, you will multiply the original (220) by .6 (this means 60 percent)

and you will get 220*.6=132

3 0

3 years ago

Read 2 more answers

What is the present value of $6,000 to be received at the end of each of eight periods, assuming the first payment occurs at the

Kipish [7]

Answer: Present value = $7200

Step-by-step explanation: Given Principal that is the original amount is $6000

Rate is 10% every fourth year

But the total period is eight.

So the interest would be paid 8/4 = 2 times.

Therefore,

Simple interest

= {principal * rate * no of times}/100

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6 0

3 years ago

25=k/5;k=5 what's the answer

SashulF [63]

25=k/5

25/5/5/1

= (25/5)(1/5)

= (5/1)(1/5)

= (5)(1)/(1)(5)

= 5/5

= 1

I hope that's help !

8 0

3 years ago

ank A contains 80 gallons of water in which 20 pounds of salt has been dissolved. Tank B contains30 gallons of water in which 5

adell [148]

Answer:

$\frac{dx}{dt}=2-\frac{3}{40}x+\frac{y}{15}$

$\frac{dy}{dt}=\frac{3}{40}x-\frac{y}{5}$

x(0)=20,y(0)=5

Step-by-step explanation:

We are given that

Tank A contains water=80 gallons

x(0)=20,y(0)=5

Tank B contains water=30 gallons

Rate=4 gallon/min

Concentration of salt is pumped into tank=0.5 pound /gallon of water

Solution pumped from tank A to tank B at the rate=6 gallons/min

Solution pumped from tank B to tank A at the rate=2gallon/min

Solution from tank B is pumped out of the system at the rate=4 gallon/min

We have to find the DE at time t

For x

Rate in= $0.5\times 4+y(t)/30\times 2$

Rate in= $2+y/15$

Rate out= $x/80\times 6$

Rate out=3x/40[/tex]

$\frac{dx}{dt}=$ Rate in-Rate out

$\frac{dx}{dt}=2+y/15-3x/40$

$\frac{dx}{dt}=2-\frac{3}{40}x+\frac{y}{15}$

For y

Rate in= $x/80\times 6$

Rate in=3/40x

Rate out= $y/30\times (4+2)$

Rate out=y/5

$\frac{dy}{dt}=$ Rate in-Rate out

$\frac{dy}{dt}=\frac{3}{40}x-\frac{y}{5}$

8 0

3 years ago

PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!

Keith_Richards [23]

It should be 7.615773106
But rounded should be 7.6

5 0

3 years ago