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kodGreya [7K]
3 years ago
5

What is the solution of 7<5-2x<17

Mathematics
1 answer:
Yakvenalex [24]3 years ago
5 0
Step Number 1. Subtract 5 from the whole equation.

7-5\ \textless \ -2x\ \textless \ 17-5

Step Number 2. Simplify

2\ \textless \ -2x\ \textless \ 12

Step Number 3. Divide the whole equation by -2

-1\ \textgreater \ x\ \textgreater \  -\frac{12}{2}

Step Number 4. Simplify

-1\ \textgreater \ x\ \textgreater \ -6

Done! :)




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1. L = 8 + W

2. 2L + 2W > 28
16 + 2W + 2W > 28

3. 4W > 12
W > 3
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What is the volume of the pyramid?<br> 8 in.<br> 7 in.<br> 6in.
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112

Step-by-step explanation:

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A lunette is a semicircular window that is sometimes placed above a doorway or above a rectangular window. A certain lunette has
soldier1979 [14.2K]

A lunette is a semi-circle, which means that it is one half of a circle. To find its area, we can find the area of the whole circle and divide it by two.

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Hope this helps!! :)

8 0
3 years ago
The difference of A and B is 3 the sum of A and B is 13 what are the values of a and b
katen-ka-za [31]

Answer:

a = 8 and b = 5

Step-by-step explanation:

A - B = 3

A + B = 13

2A = 16

A = 8

8 - B = 3

B = 5

8 0
2 years ago
Please help asap! i need to find the missing coordinate
Harrizon [31]

Answer:

8 or 32

Step-by-step explanation:

So we are given two coordinates and the length of the segment formed by those coordinates.

To find the unknown coordinate, we can use the distance formula. Let the unknown value be n:

Let's let (-2,n) be x₁ and y₁ and let (-7,20) be x₂ and y₂.

The distance formula is given by the formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute (-2,n) for x₁ and y₁ and (-7,20) for x₂ and y₂. Also, since we already know that the length is 13, substitute it for d. Thus:

(13)=\sqrt{((-7)-(-2))^2+((20)-(n))^2}

Do the operations within the parentheses:

13=\sqrt{(-7+2)^2+(20-n)^2}\\13=\sqrt{(-5)^2+(20-n)^2}

Now, square both sides to take out the square root:

(13)^2=(\sqrt{(-5)^2+(20-n)^2})^2

Simplify:

169=(-5)^2+(20-n)^2

Square (-5):

169=25+(20-n)^2

Subtract 25 from both sides. The right cancels:

(169)-25=(25+(20-n)^2)-25\\144=(20-n)^2

Now, take the square root of both sides.

\pm\sqrt{144}=\sqrt{(20-n)^2}

Simplify:

\pm12=(20-n)

So, we have two solutions:

(12=20-n)\text { or }(-12=20-n)

On the left, subtract 20. On the right, also subtract 20:

(-8=-n)\text { or }(-32=-n)

Divide both sides by -1:

(n=8)\text{ or } (n=32)

So, our two possible answers are 8 or 32.

5 0
3 years ago
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