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3 years ago

000000000000000000oowwwwwwwwwwwww

Mathematics

1 answer:

vladimir1956 [14]3 years ago

4 0

Answer:

dsasdasedssdafs

Step-by-step explanation:

dsadasdsaddsadad $\int\limits^a_b {x} \, dx$

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Change to decimals. 1. 75%

ANEK [815]

Answer: 0.75

Step-by-step explanation: To write a percent as a decimal, first remember that a percent is a ratio that compares a number to 100.

So we can think of 75% as the ratio 75 to 100 or 75 ÷ 100.

Dividing by 100 moves the decimal point two places to the left so 75 ÷ 100 will move the decimal point two places to the left which would give us .75 or 0.75.

This means that 75% can be written as the decimal 0.75.

3 0

3 years ago

Please solve this Screenshot/attachment that is included below, thanks!

amm1812

Answer:

1) A=5

Step-by-step explanation:

1) W should be greater than 1, so the only option that satisfies this is A which is 5.

(For the number line please look at the attachment)

I'm sorry, I don't know how to solve the second problem. I hope the first question helps. Sorry and Hope its clear.

6 0

3 years ago

Semicircles

Studentka2010 [4]

Answer:

The area of the shaded portion of the figure is $9.1\ cm^2$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The shaded area is equal to the area of the square less the area not shaded.

There are 4 "not shaded" regions.

step 1

Find the area of square ABCD

The area of square is equal to

$A=b^2$

where

b is the length side of the square

we have

$b=4\ cm$

substitute

$A=4^2=16\ cm^2$

step 2

We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):

The area of circle is equal to

$A=\pi r^{2}$

The diameter of the circle is equal to the length side of the square

$r=\frac{b}{2}=\frac{4}{2}=2\ cm$ ---> radius is half the diameter

substitute

$A=\pi (2)^{2}$

$A=4\pi\ cm^2$

Therefore, the area of 2 "not-shaded" regions is:

$A=(16-4\pi) \ cm^2$

and the area of 4 "not-shaded" regions is:

$A=2(16-4\pi)=(32-8\pi)\ cm^2$

step 3

Find the area of the shaded region

Remember that the area of the shaded region is the area of the square less 4 "not shaded" regions:

$A=16-(32-8\pi)=(8\pi-16)\ cm^2$

---> exact value

assume

$\pi =3.14$

substitute

$A=(8(3.14)-16)=9.1\ cm^2$

8 0

4 years ago

Anyone got answers to this? Need help asap it’s due tomorrow!!

umka2103 [35]

The figure on the left side shows the water level is at the 0.5 liter mark, ie half a liter.

1 liter = 1000 mL

0.5*1 liter = 0.5*1000 mL

0.5 liter = 500 mL

If you poured all the water into the jug on the right (without spilling), then the water level should reach the 500 mL mark. This is the small tickmark exactly halfway between the 400 and 600.

5 0

3 years ago

Please help with this question

insens350 [35]

Answer:

alternate interoir

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers