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Sergeeva-Olga [200]
3 years ago
11

The tens digit is 9 more than the ones digit

Mathematics
1 answer:
zavuch27 [327]3 years ago
6 0
This number should be 10.

The tens digit the the 1st number on a two-digit number. Because the highest number you can go without creating a hundredths place is a 9, and the question says the ones-place (the last digit), this has to make this number 0. If it were to be 1 or anything higher, it would have to create a hundredths place if the rule of the question were to be followed.

Example: 
If ones-place were 1, then following rule: 1+9 = 10
Your number would end up being 101 instead of a tenths place number.

I hope that made some sense somewhere! 
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Which gives the correct values for points A, B, C, and D?
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Answer:

<em>The correct answer is: A</em>

Step-by-step explanation:

<u>Points on a Numeric Line</u>

The numeric line shown in the figure has four points A, B, C, and D. It's clear that each marked division of the line has a value of 1/4 units and all four points are below the reference zero, thus all are negative.

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Point B is one mark above A, thus it's located at:

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The correct answer is: A

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Read 2 more answers
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2. Lack of Guidance/Support

3. Insufficient Finances

4. Academic Unpreparedness

5. Illness of family member or family issues

Step-by-step explanation:

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3 years ago
In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b
madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding (ax+by)^7 using Binomial expansion, we have that:

(ax+by)^7 =

(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7

= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7

We have that the coefficients of the first two terms are 128 and -224.

For the first term:

=> a^7 = 128

=> a = \sqrt[7]{128}\\ \\\\a = 2

For the second term:

a^6b = -224

b = \frac{-224}{a^6}

b = \frac{-224}{2^6} \\\\\\b = \frac{-224}{64} \\\\\\b = 3.5

Therefore, a = 2, b = 3.5

5 0
3 years ago
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