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Sergeeva-Olga [200]
4 years ago
11

The tens digit is 9 more than the ones digit

Mathematics
1 answer:
zavuch27 [327]4 years ago
6 0
This number should be 10.

The tens digit the the 1st number on a two-digit number. Because the highest number you can go without creating a hundredths place is a 9, and the question says the ones-place (the last digit), this has to make this number 0. If it were to be 1 or anything higher, it would have to create a hundredths place if the rule of the question were to be followed.

Example: 
If ones-place were 1, then following rule: 1+9 = 10
Your number would end up being 101 instead of a tenths place number.

I hope that made some sense somewhere! 
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Answer:

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b) For a = 1, b = 10 and c = 1, then we have:

\frac{1}{(10 + 1)} ≠ \frac{(1*1 + 1*10)}{10*1}

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Step-by-step explanation:

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Step-by-step explanation:

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