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Sergeeva-Olga [200]
3 years ago
11

The tens digit is 9 more than the ones digit

Mathematics
1 answer:
zavuch27 [327]3 years ago
6 0
This number should be 10.

The tens digit the the 1st number on a two-digit number. Because the highest number you can go without creating a hundredths place is a 9, and the question says the ones-place (the last digit), this has to make this number 0. If it were to be 1 or anything higher, it would have to create a hundredths place if the rule of the question were to be followed.

Example: 
If ones-place were 1, then following rule: 1+9 = 10
Your number would end up being 101 instead of a tenths place number.

I hope that made some sense somewhere! 
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Answer:

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2 years ago
Find the sum of the first 21 terms of the arithmetic sequence 5, -2, -9.
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Read 2 more answers
10. 5(3-9b) = 3(-15b – 2)
olga2289 [7]

Answer:

No Solution

Explanation:

5(3 - 9b) = 3(-15b – 2)

Expand

5(3 - 9b): 15 - 45b

3(-15b - 2): -45b - 6

15 - 45b = -45b - 6

Subtract 5 From Both Sides

15 - 45b - 15 = -45b - 6 - 15

Simplify

-45b = -45b - 21

Add 15b To Both Sides

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Simplify

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No Solution

8 0
3 years ago
an urn containing n balls can be represented by the set u = {b1, b2, ... , bn}. interpret the following algorithm in the context
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3 years ago
How can you write -1/4x-9 on a graph​
Dmitrij [34]

Answer:

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x... 0 , 1

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Hope this helps you out.

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