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Vika [28.1K]
3 years ago
12

Sabina makes $2,000 per month. She spends $150 on store credit and $250 on an auto loan each month. Does she have excessive debt

?
A.)Yes, because her debt-to-income ratio is higher than 36 percent.
B.)No, because her debt-to-income ratio is lower than 36 percent.
C.)No, because her debt-to-income ratio lower than 42 percent.
D.)Yes, because her debt-to-income ratio is 50 percent.
Mathematics
1 answer:
never [62]3 years ago
7 0

Answer:

The answer is B because her debt to income ratio is lower than 36 percent

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Margarita [4]
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\begin{cases}
P=1200 &\textit{in thousands}\\
t=2 &\textit{in 2002}
\end{cases}\implies 1200=1110.9e^{k2}
\\\\\\
\cfrac{1200}{1110.9}=e^{2k}\implies ln\left( \frac{1200}{1110.9} \right)=ln(e^{2k})\implies ln\left( \frac{1200}{1110.9} \right)=2k
\\\\\\
\cfrac{ln\left( \frac{1200}{1110.9} \right)}{2}=k\implies 0.0385755\approx k\implies 0.0386\approx k\\\\
-------------------------------\\\\

\bf P=1110.9e^{0.0386t}\qquad 
\begin{cases}
t=14\\
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3 0
3 years ago
I have to get this so I pass help plz
pshichka [43]

Answer:

\boxed{\sf x=-2}

\boxed{\sf y=-4}

Step-by-step explanation:

<u>First, Let's  solve for x in -2x+2y=-4:</u>

\sf -2x+2y=-4

<u>Subtract 2y from both sides:</u>

\sf -2x+2y-2y=-4-2y

\sf -2x=-4-2y

<u>Divide both sides by -2:</u>

\sf \cfrac{-2x}{-2}=-\cfrac{4}{-2}-\cfrac{2y}{-2}

\bold{ x=y+2}

<u>Now, we'll substitute x=y+2 to 3x+3y=-18:</u>

\sf 3x+3y=-18

→ let x=2+y

\sf 3\bold{(2+y)}+3y=-18

<u>Simplify:</u>

\sf 6+6y=-18

<u>Now, let's solve for y in 6+6y=-18</u>

\sf 6+6y=-18

<u>Subtract 6 from both sides:</u>

\sf 6+6y-6=-18-6

\sf 6y=-24

<u>Divide both sides by 6:</u>

\sf \cfrac{6y}{6}=\cfrac{-24}{6}

\bold{ y=-4}

<u>Now, substitute y=-4 into x=2+y:</u>

\sf x=2+y

→ let y = -4

\sf x=2+\bold{-4}

\bold{x=-2}

Therefore, x=-2 and y=-4.

<u>_____________________________________</u>

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Answer:

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Answer:

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Step-by-step explanation:

NOT NEEDED FOR THIS QUESTION

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