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3 years ago

6

10 POINTS Seventeen is 20% of what number? Enter your answer in the box.

1 answer:

Scrat [10]3 years ago

4 0

85

Also, this is 5 points.

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Plzzzzzzz help me

Andru [333]

When x varies inversely with y then you'll have
xα1/y
x=k/y where k is the proportionality constant
when x=8. y=10. k=?
8=k/10
make k the subject of the formula
k=10×8
k=80.

When x=6. y=?.k=80
6=80/y
Make y the subject of the formula
y=80/6
y=40/3

8 0

3 years ago

I WILL GIVE BRAINLY! PLEASE HELP!

wolverine [178]

Answer: 1/3 =0.33

Step-by-step explanation:

just substitute the values of x and y into the expression to get

4(2)+1 /3(3)^2

=8+1 /3×9

=9/27

=1/3

=0.33

4 0

3 years ago

Using the coordinate plane below - tell me the ordered pairs for : B, C, F, E

irina [24]

Step-by-step explanation:

B(-2,3)

C(1,0)

F(-1,-2)

E(0,-4)

5 0

3 years ago

Read 2 more answers

Help pleaseeeee it’s urgent!!!

Ad libitum [116K]

Answer:

(2,-7)

Step-by-step explanation:

Use the midpoint formula! (Attached is a picture of it!)

1) Plug in the values:

(5-1)/2,(-6+-8)/2

2) Simplify:

4/2,-14/2

3) Solve:

(2,-7)

6 0

3 years ago

Marty is asked to draw triangles with side lengths of 4 units and 2 units, and a non-included angle of 30°. Select all the trian

777dan777 [17]

Answer:

The drawn in the attached figure

see the explanation

Step-by-step explanation:

<em>First case</em>

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\B=30^o$

Applying the law of sines

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(A)}=\frac{2}{sin(30^o)}$

$sin(A)=1$

so

$A=90^o$

Find the measure of angle C

In a right triangle

we know that

$B+C=90^o$ ----> by complementary angles

$B=30^o$

therefore

$C=60^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{c}{sin(60^o)}=\frac{2}{sin(30^o)}$

$c=2\sqrt{3}\ units$

therefore

The dimensions of the triangle are

$A=90^o$

$B=30^o$

$C=60^o$

$a=4\ units\\b=2\ units\\c=2\sqrt{3}=3.46\ units$

<em>Second case</em>

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\A=30^o$

Applying the law of sines

Find the measure of angle B

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(30^o)}=\frac{2}{sin(B)}$

$sin(B)=0.25$

so

using a calculator

$B=14.48^o$

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

so

$A+B+C=180^o$

$A=30^o\\B=14.48^o$

therefore

$30^o+14.48^o+C=180^o$

$C=135.52^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{a}{sin(A)}$

substitute the given values

$\frac{c}{sin(135.52^o)}=\frac{4}{sin(30^o)}$

$c=5.61\ units$

therefore

The dimensions of the triangle are

$A=30^o$

$B=14.48^o$

$C=135.52^o$

$a=4\ units\\b=2\ units\\c=5.61\ units$

see the attached figure to better understand the problem

4 0

3 years ago