1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
12345 [234]
4 years ago
9

two cars, 330 kilometers apart begin driving toward each other on a long, straight highway. One car drives 80 kilometers per hou

r and the other 85 miles per hour. At the same time, a canary, starting on one car, flies back and forth between the cars as they approach each other. If the canary flies 90 kilometers per hour and spends no time to turn around at each car, how far has it flown when the cars collide?
Mathematics
1 answer:
miskamm [114]4 years ago
8 0
The two cars will meet when the sum of the distances covered by the two cars is 330 kilometers.

distance = speed x time.
Let the time covered when they meet be x, then:
80x + 85x = 330
165x = 330
x = 330/165 = 2 hours.

In 2 hours, the canary will cover 90 x 2 = 180 kilometers.

Therefore, the has flown 180 kilometers when the cars collide..
You might be interested in
First to help gets marked brainliest!!
Lubov Fominskaja [6]

Answer:

x: -8, -4, 0, 4

y:  6,  4,  2,  0

Equation: y = 2 - 0.5x

7 0
3 years ago
There are 7.55 grams of sugar in 5 servings of strawberries. How many grams of sugar are in a single serving of strawberries?
balandron [24]

Answer:

1.51

Step-by-step explanation:

Divide 7.55 by 5 and it equals 1.51

7 0
3 years ago
Read 2 more answers
Graph the line by plotting any two ordered pairs that satisfy the equation.
ollegr [7]

Answer:

(0,-4)

(3,0)

Step-by-step explanation:

Let start at the orgin.

This is a linear equation since the equation is in the form of

y = mx + b

where m is the slope and b is the y intercept.

Since we starting at the orgin, and b is our y intercept.

Our first point is

(0,-4).

since the slope is 4/3.

We would rise 4 from the y value and run 3 to the x value.

In other words, to find your second point, go up 4 units from the first point and move to the right 3 units.

So our next point is at

(3,0).

U can continously go up 4 units and move 3 units to the right to find other points.

6 0
3 years ago
2 tan 30°<br>II<br>1 + tan- 300​
shusha [124]

Question:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Answer:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

Step-by-step explanation:

Given

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Required

Simplify

In trigonometry:

tan(30^{\circ}) = \frac{1}{\sqrt{3}}

So, the expression becomes:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}

Simplify the denominator

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}

Express the fraction as:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= \frac{2}{\sqrt 3} / \frac{4}{3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2}{\sqrt 3} * \frac{3}{4}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{1}{\sqrt 3} * \frac{3}{2}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3}

Rationalize

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3\sqrt{3}}{2* 3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\sqrt{3}}{2}

In trigonometry:

sin(60^{\circ}) =  \frac{\sqrt{3}}{2}

Hence:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

3 0
3 years ago
Evaluate the surface integral. s xy ds s is the triangular region with vertices (1, 0, 0), (0, 8, 0), (0, 0, 8)
zmey [24]

Parameterize S by

\vec s(u,v)=(1-u)v\,\vec\imath+8uv\,\vec\jmath+8(1-v)\,\vec k

with 0\le u\le1 and 0\le v\le1.

Then the surface element is

\mathrm dS=\|\vec s_u\times\vec s_v\|\,\mathrm du\,\mathrm dv=8\sqrt{66}\,v\,\mathrm du\,\mathrm dv

and the surface integral is

\displaystyle\iint_Sxy\,\mathrm dS=8\sqrt{66}\int_0^1\int_0^18(1-u)uv^3\,\mathrm du\,\mathrm dv=\boxed{8\sqrt{\dfrac{22}3}}

4 0
3 years ago
Other questions:
  • Math<br> Needs help<br> Surface area
    6·1 answer
  • What is the value of this expression <br>1/4^−3?
    12·2 answers
  • I need help with 9-12 ASAP<br> its due tomorrow.
    13·1 answer
  • A. Vertical angle theorems. Consecutive interior angle theorem
    10·2 answers
  • Rewrite f(x) = x^2 + 4x -12 in the form that would most easily help you identify
    6·2 answers
  • A basketball player is fouled while attempting to make a basket and receives two free throws. The opposing coach believes there
    7·1 answer
  • 260.94 in word form ! i really need help w this !!
    5·2 answers
  • Can someone help me pls!!
    6·1 answer
  • In how many ways can 6 students be seated in a row of 6 seats if 2 of the students insist on sitting beside each other?
    6·1 answer
  • 2. What is the equation of the line that passes through points (-8,3/2) and (-12, 5/2)
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!