Answer:
Some of the other answers are good examples of solving a system of three equations in three unknowns, which is what this problem is asking. Though the simplest way to solve this problem is actually to notice that, if we sum the three equations, we get:
X + Y = 10
X + Z = 20
+ Y + Z = 24
----------------
2X + 2Y + 2Z = 54
Factoring out the 2, we have 2(X + Y + Z) = 54, and dividing both sides by 2 reveals that X + Y + Z = 27.
Step-by-step explanation:
hopefully this helps
To find the area of a rhombus, multiply the lengths of the two diagonals and divide by 2 (same as multiplying by 1/2): The sides and angles of a rhombus: The sides of a rhombus are all congruent (the same length.) Opposite angles of a rhombus are congruent (the same size and measure.)
A square has two perpendicular bisectors but a square is not a rhombus (because a rhombus does not have all four angles = 90. Oh, but wait, a rhombus is a square in the same way a rectangle is a square but not the other way around.
Picture?? This question is incomplete just get a picture then I can answer it
So floor that you started is x
go down 8 means -8
end on 16
so
x-8=16
add 8
x=24
started on 24
