Find the roots of each equation. 6v^2+24=0 PLEASE HELP I NEED THIS TO MOVE UP A GRADE
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Answer:
Step-by-step explanation:
- First we find the slope of the line AB passing through the point (2,0)
- line AB is perpendicular to the line
, this equation is slope intercept for, which is
so our m or slope is
- Since the slope of line AB is perpendicular to
then we use the equation
, so what do we multiply
by to get -1? -4 right, so that's the slope of line AB with the point (2,0)
- Now line CD is parallel to line AB, that means it has the same slope as AB, so slope of CD is -4
- So we make the equation
so m= -4 and our point is (-1,6)
thats the equation of line side CD
Using the classification for even and odd functions, it is found that the function is even, because f(-x) = f(x).
<h3>How we verify if the function is even, odd, or neither?</h3>- If for all values of x, f(x) = f(-x), the function is even.
- If for all values of x, f(-x) = -f(x), the function is odd.
- If neither of these statements are true, the function is neither even nor odd.
Graphing the function , for every value of x, f(x) = -f(x), that is, the function is symmetric over the y-axis, hence it is even.
More can be learned about even and odd functions at brainly.com/question/5634052
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