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neonofarm [45]
3 years ago
11

Find the missing measurement for each quadrilateral 5) this is rhombus ABCD

Mathematics
1 answer:
a_sh-v [17]3 years ago
4 0

To find the area of a rhombus, multiply the lengths of the two diagonals and divide by 2 (same as multiplying by 1/2): The sides and angles of a rhombus: The sides of a rhombus are all congruent (the same length.) Opposite angles of a rhombus are congruent (the same size and measure.)

A square has two perpendicular bisectors but a square is not a rhombus (because a rhombus does not have all four angles = 90. Oh, but wait, a rhombus is a square in the same way a rectangle is a square but not the other way around.

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Solve.<br><br> Round to the nearest hundredth.<br><br> 29.3 = 1.7y
Elena-2011 [213]

Steps to Solve:

29.3 = 1.7y

29.3/1.7 = 1.7y/1.7

y = 17.2352941176

In this case, we round up the hundredths place because the number in the thousandths place is 5 or higher.

y = 17.24

Hope this helps!! :)

7 0
3 years ago
Read 2 more answers
Does the inequality sing mean equals in an equasion
shtirl [24]
Here are the 4 inequality signs.

a < b     ---> a is less than b
a \le b    ---> a is less than or equal to b
a > b     ---> a is greater than b
a \ge b    ---> a is greater than or equal to b

For the second and fourth lines above, the two sides may or may not be equal.
For the first and third lines above, the two sides cannot be equal.

6 0
2 years ago
Scheels received a shipment of 400 water bottles. 30% were yellow.
Amanda [17]
Answer:
There were 120 yellow water bottles in the shipment

Explanation:
Multiply 400 by 30% to find out how many water bottles came in yellow.

400 • .30 = 120

So, 120 were yellow.
6 0
3 years ago
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LT1 10th grade level
Anton [14]

Answer:

The distance between the pirate and the treasure can be found from the following relationship between ΔEAF and ΔABC;

\overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC} = \overline{EF}/\overline{BC}

Step-by-step explanation:

From the question diagram, we have two triangles, ΔEAF and ΔABC;

The ratio of the lengths of the sides \overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC}

∠EAF and ∠BAC are vertical angles, therefore ∠EAF = ∠BAC

Therefore, ΔEAF and ΔABC are similar triangles by Side-Angle-Side, SAS, rule of similarity which states that two triangles that have ratios of a pair of their corresponding sides and the two sides also form equal angles within each triangle, then the two triangles are similar

Therefore, the ratio of the each pair of corresponding sides of the two triangles are equal

We have;

\overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC} = 50 ft. /(100 ft.) =  \overline{EF}/\overline{BC} = \overline{EF}/120 ft.

\overline{EF} = 120 ft. × 50 ft./(100 ft.) = 60 ft.

\overline{EF} = 60 ft.

The distance between the pirate and the treasure, \overline{EF} = 60 ft.

4 0
3 years ago
3) 3 feet = 1 yard. If a quarterback passes for 327 yards during a game.
Yuri [45]
981 feet. You have multiple 3 by 327, which is 981 feet.
7 0
2 years ago
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