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Answer:
Isobaric process between points 1 and 2 while isochoric process between 2 and 3.
Explanation:
A themodynamic equilibrium system which changes from initial state to the final state by a process is known as thermodynamic processes. There are many different kinds of thermodynamic process which depends upon the thermodynamic quantities such as pressure, volume, temperature, entropy etc. The most common thermodynamic processes are isobaric, isothermal, isochoric and adiabatic.
When the temperature of the system remains same during the thermodynamic process, the process is known as isothermal.
When the heat of the system remains same during the thermodynamic process, the process is known as adiabatic.
When the volume of the system remains same during the thermodynamic process, the process is known as isochoric.
When the pressure of the system remains same during the thermodynamic process, the process is known as isobaric.
According to the question, between points 1 and 2 pressure remains constant, hence the process is isobaric.
According to the question, between points 2 and 3 volume remains constant, hence the process is isochoric.
Answer
correct Answer is gravitation
Explanation
In 2005, collision of deep impact probe with the nucleus of comet tempel 1 was carried out. In this probe the length of Tempel 1's nucleus was about 5km long. In this probe it was revealed that the nucleus behave as a rubble pile which is held together by gravitation.
In this probe speed of Tempel 1 which is moving towards the nucleus was 10km/s. In this probe series of images was recorded and cloud of debris was analyzed,It was discovered that comet is made up of a primordial chunk of solar system material. It was observed that Tempel 1's has tiny grains of silicates, iron compounds, complex hydrocarbons, and clay and carbonates thought to require liquid water to form it was more appropriate for a cosmic souffle, as the nucleus is apparently porous and fluffy.
Answer:
2.13 x 10^-19 J or 0.53 eV
Explanation:
cut off wavelength, λo = 700 nm = 700 x 10^-9 m
λ = 400 nm = 400 x 10^-9 m
Use the energy equation

Where, K be the work function



K = 2.13 x 10^-19 J
K = 0.53 eV
The correct answer to the question is 130.4 N.
CALCULATION;
The mass of the bullet is given as m = 28 gram = 0. 028 kg.
The initial velocity of the bullet u = 55 m/s
The final velocity of the bullet v = 18 m/s.
The distance covered by the bullet through the sand bag s = 29 cm.
= 0.29 m
Let the acceleration of the bullet is a .
From equation of kinematics, we know that-

⇒ 


The negative sign is used due to the fact that force is opposing in nature. Its velocity is decreasing with time.
From Newton's second law of motion, we know that net force on a body is equal to the product of mass with acceleration.
Mathematically F = ma.
Hence, the frictional force exerted on the bullet is calculated as -
F = m × a
= 0.028 × (-4656.897) N
= -130.4 N [ANS]
Here, N ( newton) stands for the unit of force.