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ollegr [7]
3 years ago
14

Why are theories excepted as true

Physics
2 answers:
patriot [66]3 years ago
5 0
The top person is cheesy
Airida [17]3 years ago
4 0

Answer:

A theory not only explains known facts; it also allows scientists to make predictions of what they should observe if a theory is true. Scientific theories are testable. New evidence should be compatible with a theory. If it isn't, the theory is refined or rejected.

Explanation:

Please mark as brainliest! Thanks!

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A wave along a guitar string has a frequency of 540 Hz and a wavelength of 4.3 m. Calculate the velocity of the wave.
Virty [35]

Answer:

Velocity of wave =  2322 m /sec

Explanation:

We know that, Velocity of wave v = n  λ

Given, n = 540 Hz,  λ=4.3 m , v = ?

Putting the value of n and λ

Velocity of wave = 540 x 4.3 = 2322 m /sec

8 0
3 years ago
Read 2 more answers
The speed of light in a transparent medium is 0.6 times that of its speed in vacuum. Find the refractive index of the medium.
grin007 [14]
<h2>Answer:</h2>

The refractive index is 1.66

<h2>Explanation:</h2>

The speed of light in a transparent medium is 0.6 times that of its speed in vacuum .

Refractive index of medium = speed of light in vacuum / speed of light in medium  

So

RI = 1/0.6 = 5/3 or 1.66

3 0
3 years ago
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When atoms _____, they break down into atoms of different elements and release energy.
SCORPION-xisa [38]

Answer:

It may be combine?

Do you have multiple choice i can see?

Explanation:

5 0
3 years ago
How is a scientific theory different from a hypothesis?
Maslowich
A scientific theory is different from a hypothesis because a theory is a educated guess that is being worked on and proven correct and a hypothesis is a educated guess it is a guess that needs to be proven.
7 0
4 years ago
The electron beam inside an old television picture tube is 0.40 mm in diameter and carries a current of 50 μA. This electron bea
Galina-37 [17]

Answer:

A) J= 398 A/m²

B) E= 1.6×10⁶ N/C

C) P= ×10⁴ W

Explanation:

My work is in the attachment. Comment with questions or if something seems wrong with my work. (Honestly, they seem little high but it could just be the given numbers being unrealistic.) Below I have explanations of each part to match up with the image as well.

Part A:

Current density (J) is defined as the amount of current in a particular cross-sectional area. To get this, we simply need to divide the current (I) by the cross-sectional area of the electron beam tube (A).

Part B:

This one took the most work for me. I used a kinematic equation (yes they apply to electrons) to find the electric field (E). I used a modified form of the familiar: ∆d=V₀τ+aτ²/2

We can use the fact that τ= V/a, a=(qE/m), and V₀=0 here to rewrite the equation in terms of values we know and/or can look up. From there we solve for E and plug in the values.

Part C:

Power (P) is simply work (W) over time (τ). We know what τ is from before and can take W= mV²/2. Plugging these in and reducing some values gives us an equation for power as well.

5 0
3 years ago
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