All categories

3 years ago

What are Newton’s 3 laws

Physics

2 answers:

Vladimir79 [104]3 years ago

3 0

Newton's First Law of Motion:

I. Every object in a state of uniform motion tends to remain in that state of motion unless an external force is applied to it.

Newton's Second Law of Motion:

II. The relationship between an object's mass m, its acceleration a, and the applied force F is F = ma. Acceleration and force are vectors (as indicated by their symbols being displayed in slant bold font); in this law the direction of the force vector is the same as the direction of the acceleration vector.

Newton's Third Law of Motion:

III. For every action there is an equal and opposite reaction.

Amanda [17]3 years ago

3 0

1) an object at rest tends to stay at rest and an object in motion tends to stay in motion with the same direction and speed unless an unbalanced force acts upon it

2) The second law shows that if you exert the same force on two objects of different masses you will get different accelerations does acceleration on the smaller mass will be greater the effect of 1 10 newton force on a baseball would be much greater than that force acting on a truck the difference in acceleration is (Technically Force=Mass x Acceleration or F=MA)

3) For every action force there is an equal and opposite reaction

You might be interested in

Renewable resources need to be conserved because

creativ13 [48]

Answer:

(A) We are using them faster than they are replenished by nature

4 0

3 years ago

Find the magnitude of the impulse delivered to a soccer ball when a player kicks it with a force of 1450 N . Assume that the pla

juin [17]

To solve this problem we will apply the concept of Impulse. Which is described as the product between the Force and the change in time. Mathematically this can be described as

$I = F \Delta t$

Where,

F = Force

$\Delta t$ = Time

Our values are given as,

F = 1450N

$\Delta t = 5.1*10^{-3} s$

Replacing we have,

$I = (1450)(5.1*10^{-3})$

$I = 7.395Kg\cdot m/s$

Therefore the impulse delivered to the soccer ball is $7.395Kg\cdot m/s$ or $7.395N\cdot s$

4 0

3 years ago

A parachutist bails out and freely falls 63 m. Then the parachute opens, and thereafter she decelerates at 1.5 m/s2. She reaches

yaroslaw [1]

Answer:

(a) The parachutist spent 24.84 secs in air

(b) The height the fall begins is 472 m

Explanation:

Here is the complete question:

A parachutist bails out and freely falls 63 m. Then the parachute opens, and thereafter she decelerates at 1.5 m/s2. She reaches the ground with a speed of 3.3 m/s. (a) How long is the parachutist in the air (b) At what height does the fall begin?

Explanation:

From one of the equations of kinematics for free fall

$H = ut - \frac{1}{2}gt^{2}$

Where H is the height

u is the initial velocity

t is the time

and g is the acceleration due to gravity (Take g = 9.8 m/s2)

Now, we can find the time spent before the parachute opens.

u = 0 m/s (we assume the parachutist starts from rest)

H = - 63 m

∴ $-63 = 0(t) - \frac{1}{2}(0.98) t^{2} \\-63 = -4.9 t\\t^{2} = \frac{63}{4.9} \\t^{2} = 12.86\\t = \sqrt{12.86} \\t = 3.59 s$

This the time spent before the parachute opens

Also from one of the equations of kinematics for free fall

$v = u - gt$

where v is the final velocity

We can determine the final velocity before the parachute opens and she starts to decelerate

∴ $v = - 9.8(3.59)\\v = - 35.18m/s$

Now, we will calculate the time spent after the parachute opens

From one of the equation of kinematics for linear motion,

$v = u + at$

Here, the initial velocity will be the final velocity just before the parachute opens, that is

$u = - 35.18 m/s$

From the question,

$v = - 3.3 m/s$

$a = 1.5 m/s^{2}$

We then get

$-3.3 = - 35.18 + (1.5)t$

$-3.3 + 35.18 = 1.5t\\31.88 = 1.5t$

$t = \frac{31.88}{1.5}$

$t = 21.25 secs$

(a) To determine how long the parachutist is in the air,

That is sum of the time used when falling freely and the time used after the parachute opens

= 3.59 secs + 21.25 secs

24.84 secs

Hence, the parachutist spent 24.84 secs in air

(b) To determine what height the fall begins

First, we will calculate the height from which the parachute opens

From one of the equation of kinematics for linear motion,

$x = ut + \frac{1}{2}at^{2} \\$

$x = -35.18(21.25) + \frac{1}{2}(1.5)(21.25)^{2} \\x = -747.58 + 338.67\\x = -408.91m\\$

$x$ ≅ $- 409m$

Hence, the height the fall begins is 63m + 409m

= 472 m

3 0

3 years ago

A deuterium nucleus consists of one proton and

ser-zykov [4K]

A proton consists of 2 up quarks and 1 down quark.
A neutron consists of 1 up quark and 2 down quarks.

A deuterium nucleus consists of one proton and one neutron, so its quark composition is (3) 3 up quarks and 3 down quarks.

5 0

3 years ago

Major storms get their energy from WATER VAPOR in the air. Which step of the water cycle would give energy to a storm

IrinaK [193]

Evaporation is the process of water being evaporated and rising. This water vapor condenses at a certain point and mixes with aerosols to create a cloud.

7 0

3 years ago