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sladkih [1.3K]
3 years ago
5

Mo bisects lmn m lmn 6x-28 m lmo x+34. find m

Mathematics
2 answers:
garri49 [273]3 years ago
8 0
LMO+NMO = LMN,
x+34 + NMO = 6x-28
But, MO bisects LMN, so LMO=NMO
x+34 + x+34 = 6x-28
2x+68 = 6x-28
4x = 96
x = 24
That would makem it
24 + 34 =58 T NMO = 6(24)-28
58 + nmo = 144 - 28 = 119
116- 58 = 58
serg [7]3 years ago
6 0

1. B

2. C

3. B

4. C

5. A

6. A

7. C

8. A

9. D

10. C

11. B

12. B


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Answer:

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Step-by-step explanation:

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Answer:

This is easy -- it's just a list of steps.  At this level, the problems are pretty simple.

Let's just do one, then I'll write out the list of steps for you.

Find the inverse of f( x ) = -( 1 / 3 )x + 1

STEP 1:  Stick a "y" in for the "f(x)" guy:

y = -( 1 / 3 )x + 1

STEP 2:  Switch the x and y

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x = -( 1 / 3 )y + 1

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x = -( 1 / 3 )y + 1 ... multiply by 3 to ditch the fraction ... 3x = -y + 3 ... ditch the +3 ... subtract 3 from both sides ... 3x - 3 = -y ... multiply by -1 ... -3x + 3 = y ... y = -3x + 3

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Step-by-step explanation:

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Step-by-step explanation:

Given:

Two triangles ABC and FED.

m∠A = m∠B

m∠C = m∠A + 30°

m∠E = m∠F = x

m∠D = 2x-20°.

Now, let m∠A = m∠B = y

So, m∠C = m∠A + 30° = y+30

Now, sum of all interior angles of a triangle is 180°. Therefore,

m∠A + m∠B +  m∠C = 180

y+y+y+30=180\\3y=180-30\\3y=150\\y=\frac{150}{3}=50

Therefore, m∠A = 50°, m∠B = 50° and m∠C =  m∠A + 30° = 50 + 30 = 80°.

Now, consider triangle FED,

m∠D+ m∠E + m∠F = 180

2x-20+x+x=180\\4x=180+20\\4x=200\\x=\frac{200}{4}=50

Therefore,  m∠F = 50°  

m∠E = 50° and  

m∠D =  2x-20=2(50)-20=100-20=80\°

So, both the triangles have congruent corresponding angle measures.

m∠A = m∠F = 50°

m∠B = m∠E = 50°

m∠C = m∠D = 80°

Therefore, the two triangles are similar by AA postulate.

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3 years ago
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Mamont248 [21]

Answer:

1e+120

Step-by-step explanation:

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