You could do the question the way it is written, but it is far easier to bring the negative power up to the numerator.
y= x^2 - 3. The derivative of that is
dy/dx = 2x The three is a constant and is always dropped when a derivative is taken
d(-3)/dx = 0
If you are a purist and want to solve the question the way it is written, you could do it this way.
dy/dx = d(1)/dx x^-2 - d(x^-2)/dx * 1
======================
(x^-2)^2
dy/dx = - (-2 x^ - 3) / x^-4
dy/dx = 2 x^-3 * x^4
dy/dx = 2 x^(-3 + 4)
dy/dx = 2x ^ 1
dy/dx = 2x <<<<< answer
The answer is Beryllium atom has a larger radius by 2 times.
Nitrogen atom: 5.6 × 10⁻¹¹ = 5.6 × 10⁻¹⁻¹⁰ = 5.6 × 10⁻¹ × 10⁻¹⁰ = 0.56 × 10⁻¹⁰
Beryllium atom: 1.12 × 10⁻¹⁰
Since 1.12 is bigger than 0.56, then the radius of beryllium atom is larger of the radius of nitrogen atom. Let's see by how many times:
1.12 × 10⁻¹⁰ : 0.56 × 10⁻¹⁰ = 1.12 : 0.56 = 2
C would be the odd one out, it is the only one that doesn't mean subtracting 5 from m
Answer:
k = -4
Step-by-step explanation:
Given system of equations are,
-3x-3y = h
-4x + ky = 10
We have to find the values of h and k such that system of equations has no solution.
The standard form of system of equation in two variables can be given by,
And condition for the system of equations has no solution is given by,
So, by comparing the standard form of equations with given equations, the condition such that system has no solution can be written as,
=> k = -4
and 
So, the value of h and k for above given system of equations is
and k = -4.
