One number is 8 more than another number, and their sum is 20. Find the numbers.
2 answers:
Answer:
The numbers are 6 and 14
Step-by-step explanation:
Say the unknown numbers are x and y
Say y = 8+x ................... eqn 1
and x + y = 20 ................ eqn 2
Then if you replace y by 8+x, eqn 1 becomes
x + 8 + x = 20
Collect the like terms
x + x = 20 - 8
2x = 12
Divide both sides by 2
x = 12/6
x = 6
Then to get y, substitute 6 for x in eqn 1, and we will have
y = 8 + 6
y = 14
Answer:
First number=6
Second number=14
Step-by-step explanation:
Let the first number be x
So the second number is x+8
So the sum of the two is
X+x+8=20
2x+8=20
2x=20-8
2x=12
X=12/2
=6
The second number will x+8
So 6+8=14
First number=6
Second number=14
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