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allochka39001 [22]
4 years ago
6

Helppppp please my is on the line

Mathematics
1 answer:
s344n2d4d5 [400]4 years ago
3 0

Answer:

i wanna say .05

Step-by-step explanation:

i did the two numbers divided then just rounded the decimal

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Solve the system ... y=3x-8 and y=-9x+4
natita [175]
1] y - 3x = -8
[2] y + 9x = 4

-3x + y = -8 9x + y = 4

Solve equation [2] for the variable y


[2] y = -9x + 4

// Plug this in for variable y in equation [1]

[1] (-9x+4) - 3x = -8
[1] - 12x = -12
// Solve equation [1] for the variable x


[1] 12x = 12

[1] x = 1
// By now we know this much :

y = -9x+4
x = 1
// Use the x value to solve for y

y = -9(1)+4 = -5

{y,x} = {-5,1}
7 0
3 years ago
What values of b satisfy 3(2b + 3)2 = 36?
KiRa [710]

the correct question is

What values of b satisfy 3(2b+3)^2 = 36


we have

3(2b+3)^2 = 36

Divide both sides by 3

(2b+3)^2 = 12

take the square root of both sides

( 2b+3)} =(+ /-) \sqrt{12} \\ 2b=(+ /-) \sqrt{12}-3


b1=\frac{\sqrt{12}}{2} -\frac{3}{2}

b1=\sqrt{3} -\frac{3}{2}


b2=\frac{-\sqrt{12}}{2} -\frac{3}{2}

b2=-\sqrt{3} -\frac{3}{2}

therefore


the answer is

the values of b are

b1=\sqrt{3} -\frac{3}{2}

b2=-\sqrt{3} -\frac{3}{2}


6 0
3 years ago
Read 2 more answers
For f(x) = 2x – 3 find f(-1/4)
Firdavs [7]

9514 1404 393

Answer:

  -3 1/2

Step-by-step explanation:

Put the argument where the variable is and do the arithmetic.

  f(-1/4) = 2(-1/4) -3 = -1/2 -3

  f(-1/4) = -(3 1/2)

5 0
3 years ago
Ben enters four events in an athletics competition. The probability of him winning each of the event is shown below
Kryger [21]

Answer:

Hi I need to get another chance to go back to school subject1

8 0
2 years ago
{362 – [63 + (48 ÷ 2) x 2]} + 3(9 +4)
Julli [10]

Answer:

  • 290

Step-by-step explanation:

<u>Solving with one operation at each step:</u>

  • {362 – [63 + (48 ÷ 2) x 2]} + 3(9 +4) =
  • {362 – [63 + 24 x 2]} + 3(9 +4) =
  • [362 – (63 + 48)] + 3(9 +4) =
  • (362 – 111) + 3(9 +4) =
  • 251 + 3(13) =
  • 251 + 39 =
  • 290
6 0
3 years ago
Read 2 more answers
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