All categories

3 years ago

Solve the right triangle. Round decimal answers to the nearest tenth. find the sides and angles

Mathematics

1 answer:

babymother [125]3 years ago

4 0

Answer:

b = 12.6

Step-by-step explanation:

a*2 + b*2 = c*2

6*2 + b*2 = 14*2

36 + b*2 = 196

Subtract 36 from both sides

36 + b*2 = 196

-36 -36

b*2 = 160

Find the square root of both

b = 12.64911064 or 12.6

You might be interested in

A college chemistry teacher wants to know whether taking a practice

Natalka [10]

brainly.com/question/17278316

7 0

2 years ago

X- 12 = 5x2 in standard form

Rudik [331]

Answer:

It is: -5x^2 + x - 12 = 0

Step-by-step explanation:

4 0

3 years ago

Write (2x - 5)2 as a trinomial.

solniwko [45]

Answer:

$4x^2-20x+25$

Step-by-step explanation:

$(2x-5)^{2} \\(2x)^2+2(2x)(-5)+(-5)^2\\4x^2-20x+25$

7 0

3 years ago

Read 2 more answers

1. You are conducting a survey of the people in the United States to find out how popular racket sports (tennis, badminton, racq

andrey2020 [161]

Answer:

i think it's d

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Apply Crammer's Rule to find the solution to the following quations .2x + 3y = 1, 3x + y = 5

Bond [772]

Answer:

The solution to the equation system given is:

<u>x = 2</u>
<u>y = -1</u>

Step-by-step explanation:

First, we must know the equations given:

2x + 3y = 1
3x + y = 5

Following Crammer's Rule, we have the matrix form:

$\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] =\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]$

Now we solve using the determinants:

$x=\frac{\left[\begin{array}{ccc}1&3\\5&1\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(1*1)-(5*3)}{(2*1)-(3*3)} = \frac{1-15}{2-9} =\frac{-14}{-7} = 2$

$y=\frac{\left[\begin{array}{ccc}2&1\\3&5\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(2*5)-(3*1)}{(2*1)-(3*3)}=\frac{10-3}{2-9} =\frac{7}{-7}=-1$

Now, we can find the answer which is x= 2 and y= -1, we can replace these values in the equation to confirm the results are right, with the first equation:

2x + 3y = 1
2(2) + 3(-1)= 1
4 - 3 = 1
1 = 1

And, with the second equation:

3x + y = 5
3(2) + (-1) = 5
6 - 1 = 5
5 = 5

4 0

2 years ago