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Pavel [41]
3 years ago
7

What is the answer to this

Mathematics
1 answer:
GalinKa [24]3 years ago
3 0

2, 67, and 83 are all prime. 63 and 91 are composite. For the bottom question the answer is A and B.

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Can someone please help me
svet-max [94.6K]

Answer:

12

Step-by-step explanation:

You look at the graph seeing before the 20, that one has 4 and rhe other has 8. Add 8 and 4 to get 12.

8 0
3 years ago
Read 2 more answers
Please solve this Screenshot/attachment that is included below, thanks!
amm1812

Answer:

1) A=5  

Step-by-step explanation:

1) W should be greater than 1, so the only option that satisfies this is A which is 5.  

(For the number line please look at the attachment)

I'm sorry, I don't know how to solve the second problem. I hope the first question helps. Sorry and Hope its clear.

6 0
2 years ago
Which expression is equivalent to 9p-3p +2
Dafna1 [17]
You have the right answer 6p+2
5 0
2 years ago
In △ABC, AB = 13.2m,
luda_lava [24]

Answer:

(i) ∠ABH  = 14.5°

(ii) The length of AH = 4.6 m

Step-by-step explanation:

To solve the problem, we will follow the steps below;

(i)Finding  ∠ABH

first lets find <HBC

<BHC + <HBC + <BCH  = 180°  (Sum of interior angle in a polygon)

46° + <HBC  + 90 = 180°

 <HBC+ 136°  = 180°

subtract 136 from both-side of the equation

 <HBC+ 136° - 136°  = 180° -136°

 <HBC  = 44°

lets find <ABC

To do that, we need to first find <BAC

Using the sine rule

\frac{sin A}{a} =  \frac{sin C}{c}

A = ?

a=6.9

C=90

c=13.2

\frac{sin A}{6.9} = \frac{sin 90}{13.2}

sin A = 6.9 sin 90  /13.2

sinA = 0.522727

A = sin⁻¹ ( 0.522727)

A ≈ 31.5 °

<BAC  = 31.5°

<BAC + <ABC + <BCA = 180° (sum of interior angle of a triangle)

31.5° +<ABC + 90° = 180°

<ABC  + 121.5°  = 180°

subtract 121.5° from both-side of the equation

<ABC  + 121.5° - 121.5°  = 180° - 121.5°

<ABC = 58.5°

<ABH = <ABC - <HBC

           =58.5° - 44°

            =14.5°

∠ABH = 14.5°

(ii) Finding the length of AH

To find length AH, we need to first find ∠AHB

<AHB + <BHC = 180°  ( angle on a straight line)

<AHB + 46° = 180°

subtract 46° from both-side of the equation

<AHB + 46°- 46° = 180° - 46°

<AHB  = 134°

Using sine rule,

\frac{sin 134}{13.2}  = \frac{sin 14.5}{AH}

AH = 13.2 sin 14.5 / sin 134

AH≈4.6 m

length AH = 4.6 m

8 0
2 years ago
A triangle has sides of (2x), (x - 7) and (3x - 20).
LiRa [457]
2x+x-7+3x-20=87cm
6x-27=87
6x=114
x=19
Therefore the sides are:12cm, 38cm, and 37cm
7 0
3 years ago
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