So if you subtract the 0 out from the left side, the equation is now
. Since a x is common in both of the terms on the left side, you can factor it out, now making the equation look like
. When factoring, each of the separate things (x and (x-3)), must equal zero while the other one doesn't matter. So in order for the equation to be 0, the only potential options for x is 0 and 3. Therefore x=0 and x=3 are the two solutions
The answer is 131.
-2-14 is -16
-16+147= 131
Answer:
option d
Step-by-step explanation:
Given that a coin is tossed 5 times. Assuming it is a fair coin, head and tail are equally likely.
If we toss 5 times, the number of heads can be either 0 or 1 or 2...5.
Number of outcomes that have 2 heads
=out of 5, two heads and three tails
=5C2
=5(4)/2
=10
So answeris 10
Option d is right answer
Answer:
-2
Step-by-step explanation:
(-3x/2) - 3 = 3
add 3 to both sides
(-3x/2) = 3
multiply both sides by 2
-3x = 6
divide both sides by -3
x= -2