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snow_tiger [21]
3 years ago
7

The proof that UX ≅ SV is shown. Given: △STU an equilateral triangle ∠TXU ≅ ∠TVS Prove: UX ≅ SV What is the missing statement in

the proof? Statement Reason 1. ∠TXU ≅ ∠TVS 1. given 2. ∠STV ≅ ∠UTX 2. reflex. prop. 3. △STU is an equilateral triangle 3. given 4. ST ≅ UT 4. sides of an equilat. △ are ≅ 5. ? 5. AAS 6. UX ≅ SV 6. CPCTC
Mathematics
2 answers:
iren2701 [21]3 years ago
6 0
Triangle STU is congruent to triangle UTX is the missing step. AAS (angle-angle-side) is a method of proving 2 triangles congruent, and using the already proved information, you can find the triangles that are congruent by AAS.
Tanzania [10]3 years ago
6 0

Answer:

5. Statement: \triangle TXU\cong \triangle TSV

Step-by-step explanation:

Given, triangle STU is an equilateral triangle.

\angle TXU \cong \angle TVS

To prove that UX \cong SV

Proof:

1. Statement: \angle TXU \cong \angle TVS

Reason: Given in question .

2. Statement: \angle STV \cong \angle UTX

Reason: By using reflection proeperty of rotation.

3. Statement: \triangle STU is an equilateral triangle.

Reason: \angle STU= \angle TSU=\angle SUT given.

4. Statement: ST \cong UT

Reason: Sides of equilateral triangle STU.

5. \tringle TXU \cong \triangle TSV

Reason: AAS congruence property of triangle.

6. Statement: UX\cong SV

Reason: CPCT ( corresponding parts of congruence triangles).

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Which equations represent the line that is parallel to 3x − 4y = 7 and passes through the point (−4, −2)? Select two options.
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Answer:

2 and 5

Step-by-step explanation:

The slope-intercept form of a line is y=mx-b where m is slope and b is y-intercept.

The point-slope form of a line is y-y1=m(x-x1) where m is the slope and (x1,y1) is a point on the line.

The standard form a line is ax+by=c.

So anyways parallel lines have the same slope.

So if we are looking for a line parallel to 3x-4y=7 then we need to know the slope of this line so we can find the slope of our parallel line.

3x-4y=7

Goal: Put into slope-intercept form

3x-4y=7

Subtract 3x on both sides:

  -4y=-3x+7

Divide both sides by -4:

   y=\frac{-3}{-4}x+\frac{7}{-4}

Simplify:

   y=\frac{3}{4}x+\frac{-7}{4}

So the slope of this line is 3/4.  So our line that is parallel to this one will have this same slope.

So we know our line should be in the form of y=\frac{3}{4}x+b.

To find b we will use the point that is suppose to be on our new line here which is (x,y)=(-4,-2).

So plugging this in to solve for b now:

-2=\frac{3}{4}(-4)+b

-2=-3+b

3-2=b

b=1

so the equation of our line in slope-intercept form is y=\frac{3}{4}x+1

So that isn't option 1 because the slope is different.  That was the only option that was in slope-intercept form.

The standard form of a line is ax+by=c and we have 2 options that look like that.

So let's rearrange the line that we just found into that form.

y=\frac{3}{4}x+1

Clear the fractions because we only want integer coefficients by multiplying both sides by 4.

This gives us:

4y=3x+4

Subtract 3x on both sides:

-3x+4y=4

I don't see this option either.

Multiply both sides by -1:

3x-4y=-4

I do see this as a option. So far the only option that works is 2.

Let's look at point slope form now.

We had the point that our line went through was (x1,y1)=(-4,-2) and the slope,m, was 3/4 (we found this earlier).

y-y1=m(x-x1)

Plug in like so:

y-(-2)=3/4(x-(-4))

y+2=3/4 (x+4)

So option 5 looks good too.

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