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sergey [27]
3 years ago
5

A circle has a center of (5,-5) and goes through (6,-2). What is the radius?

Mathematics
1 answer:
Fittoniya [83]3 years ago
6 0
Start with the equation of a circle whose center is at (h,k) and whose radius is r:

(x-h)^2 + (y-k)^2 = r^2

Substituting the given coordinates of the center:

(x-5)^2 + (y-[-5])^2 = r^2, or (x-5)^2 + (y+5)^2 = r^2

Substituding the given coordinates of a point (6,-2) on the circle:

(6-5)^2 + (-2+5)^2 = r^2

Simplifying:

1^2 + 3^2 = r^2, or 1 + 9 = r^2, or 10= r^2.  Then r = sqrt(10).

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Step-by-Step Explanation:

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If the limit of f(x) as x approaches 8 is 3, can you conclude anything about f(8)?
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If the limit of f(x) as x approaches 8 is 3, can you conclude anything about f(8)? The answer is No. We cannot. See the explanation below.

<h3>What is the justification for the above position?</h3>

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This is particularly clear when we consider a question with a gap. A rational function with a hole is an excellent example that will help you answer this question.

The limit of a function at a position where there is a hole in the function will exist, but the value of the function will not.

<h3>What is limit in Math?</h3>

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Limits are used to set continuity, derivatives, and integrals in calculus and mathematical analysis.

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