Write the equation what is 39% of 71

Mathematics

1 answer:

tangare [24]3 years ago

3 0

Change the percent to a decimal then multiply
.39(71)=27.69

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In a basketball game, a regular basket was worth 2 points and a long-distance basket was worth 3 points. if there were 45 basket

IgorLugansk [536]

Let
x: number of regular basketball
y: number of long-distance basket
We have the following system of equations:
2x + 3y = 96
x + y = 45
Solving the system we have
y = 45-x
2x + 3 (45-x) = 96
2x +135 -3x = 96
-x = 96 -135
x = 39
Then,
y = 45-x
y = 45-39
y = 6
answer
were made
regular baskets = 39
long-distance baskets = 6

3 0

4 years ago

At its peak, an online shopping site was selling about 420420 items per second. At this rate, how many items would it sell in 30

EastWind [94]

Answer:

756.000.

Step-by-step explanation:

That is 420 * 1800

= 756.000

3 0

3 years ago

Please help me someone

posledela

To solve this, you need to know three exponent rules:
1) Power of a product
Basically says $(ab)^{2} = a^{2} b^{2}$ . This means a product raised to a power is the same as taking each factor to that power and multiplying them.

For example: $(5a)^{2} = 5^{2} a^{2}$

2) Product of powers
Basically says $a^{m} a^{n} = a^{m+n}$ . When two expressions with the same base (a) are multiplied, you can add their exponents while keeping the same base.

For example: $a^{2} a^{3} = a^{2+3} = a^{5}$

3) Power of a power
Basically says $(a^{m})^{n} = a^{m \times n}$ . When an exponent is being raised to a exponent, you can multiply the exponents.

For example: $(a^{2})^{3} = a^{(2 \times 3)} = a^{6}$
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Back to your problem:
You are asked to simplify $(6x^{2} y)^{2} (y^{2})^{3}$ , Tackle it by simplifying both factors and then multiplying them together and simplifying again.

1) First use the power of a product rule to change $(6x^{2} y)^{2}$ into $6^{2} (x^{2})^{2} y^{2}$ . Simplify it into $
36 x^{4} y^{2}$ using the power of a power rule.

2) Simplify $(y^{2})^{3}$ into $y^{6}$ using the power of a power rule.

3) Multiply the simplified factors from part one and two and simplify using the product of powers rule:
$(36 x^{4} y^{2})(y^{6})\\
= (36 x^{4})(y^{2} y^{6})\\
= (36 x^{4})(y^{2+6}) \\
= 36 x^{4}y^{8}$

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Answer: $36 x^{4}y^{8}$