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12345 [234]
3 years ago
14

Please help me someone

Mathematics
1 answer:
posledela3 years ago
6 0
To solve this, you need to know three exponent rules:
1) Power of a product
Basically says (ab)^{2} =  a^{2}  b^{2}. This means a product raised to a power is the same as taking each factor to that power and multiplying them.

For example: (5a)^{2}  = 5^{2} a^{2}

2) Product of powers
Basically says a^{m}  a^{n} =  a^{m+n}. When two expressions with the same base (a) are multiplied, you can add their exponents while keeping the same base.

For example: a^{2}  a^{3} = a^{2+3} =  a^{5}

3) Power of a power
Basically says (a^{m})^{n} =  a^{m \times n}. When an exponent is being raised to a exponent, you can multiply the exponents.

For example: (a^{2})^{3} = a^{(2 \times 3)} =  a^{6}
----

Back to your problem:
You are asked to simplify (6x^{2} y)^{2} (y^{2})^{3}, Tackle it by simplifying both factors and then multiplying them together and simplifying again.

1) First use the power of a product rule to change (6x^{2} y)^{2} into 6^{2}  (x^{2})^{2}  y^{2}. Simplify it into 
36 x^{4}  y^{2} using the power of a power rule.

2) Simplify (y^{2})^{3} into y^{6} using the power of a power rule.

3) Multiply the simplified factors from part one and two and simplify using the product of powers rule:
(36 x^{4} y^{2})(y^{6})\\
= (36 x^{4})(y^{2} y^{6})\\
= (36 x^{4})(y^{2+6}) \\
= 36 x^{4}y^{8}

---

Answer: 36 x^{4}y^{8}
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Make t the subject of the formula <br> P= 3-2t<br> —————<br> 4+t
Rufina [12.5K]

Answer:

t = \frac{3 - 4p}{p + 2}

Step-by-step explanation:

Given

P = \frac{3 - 2t}{4 + t}

Required

Make t the subject

P = \frac{3 - 2t}{4 + t}

Cross Multiply

P * (4 + t) = 3 - 2t

4p + tp = 3 - 2t

Collect Like Terms

tp + 2t = 3 - 4p

Factorize:

t(p+2) = 3 - 4p

Make t the subject

t = \frac{3 - 4p}{p + 2}

5 0
3 years ago
What is the number of subsets of S= {1, 2, 3…10} that contain five element include 3 or 4 but not both?
Ivenika [448]

Answer:

140

Step-by-step explanation:

To construct a subset of S with said property, we have two choices, include 3 in the subset or include four in the subset. These events are mutually exclusive because 3 and 4 can not both be elements of the subset.

First, let's count the number of subsets that contain the element 3.

Any of such subsets has five elements, but since 3 is already an element, we only have to select four elements to complete it. The four elements must be different from 3 and 4 (3 cannot be selected twice and the condition does not allow to select 4), so there are eight elements to select from. The number of ways of doing this is {}_8C_4=70.

Now, let's count the number of subsets that contain the element 4.

4 is already an element thus we have to select other four elements . The four elements must be different from 3 and 4 (4 cannot be selected twice and the condition does not allow to select 3), so there are eight elements to select from, so this can be done in {}_8C_4=70 ways.

We conclude that there are 70+70=140 required subsets of S.

7 0
3 years ago
Pls do with the working
saveliy_v [14]

Answer:

2) 70,000

Step-by-step explanation:

since they have said estimate meaning frist round off

679 rounds up to 700 and 98 rounds up to 100

700×100

70000

4 0
3 years ago
Help!!!!!!!!!!!!!!!!!!!!
natima [27]
Expression: 3⁴ . 2³

= 3 * 3 * 3 * 3 * 2 * 2 * 2

= 81 * 8

= 648

In short, Your Answer would be: 648

Hope this helps!
3 0
3 years ago
Read 2 more answers
I don’t understand plsss helppp
Goshia [24]

Answer:

gyuggbgzsZdxfghuiguyftdrtffyurtyryjjb

Step-by-step explanation:

5 0
2 years ago
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