Mice...........................................
Answer:
See the answer below
Explanation:
<em>Recall that the law of dilution states that the number of moles before dilution must be equal to the number of moles after dilution.</em>
Mathematically,
molarity x number of moles before dilution = molarity x number of moles after dilution.
For solution A: final molarity = 3 mM, final volume = 2mL, initial molarity of KMnO4 = 10 mM
Applying the equation:
10 x initial volume = 3 x 2
initial volume = 6/10 = 0.6
<u>Hence, Tube A should be made with 0.6 mL of 10 mM KMnO4 stock and 1.4 mL of distilled water to give a solution of 2 mL 3 mM KMnO4.</u>
For solution B:final molarity = 8 mM, final volume = 2 mL, initial molarity = 10 mM
10 x initial volume = 8 x 2
initial volume = 16/10 = 1.6
<u>Hence, Tube B should be made with 1.6 mL of 10 mM KMnO4 stock and 0.4 mL of distilled water to give a solution of 2 mL 8mM KMnO4. </u>
"The hypothesis is always supported in the end" is the one statement among the following that <span>is true about the scientific process. The correct option among all the options that are given in the question is the first option. I hope that this is the answer that has actually come to your help.</span>
Its either A or C but im sorry i dont know which one
Answer: Yes, Endocytosis and exocytosis can occur in the same cell. It is how a cell transport and export material in and out.
Explanation: Hope this helps :) and amazing question btw
