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Tasya [4]
3 years ago
15

Write a problem for the equation x-5=2

Mathematics
2 answers:
larisa86 [58]3 years ago
6 0
Tim has 7 hotdogs he had sold 5 of them.Now Tim has 2 hot dogs left
hope this helped
sorry for my bad English
ratelena [41]3 years ago
6 0
Bob gave colin 5 cards and he was left with 2. how many cards did bob start with
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1. Isosceles Triangle The two equal sides of an isosceles triangle are each 42
gavmur [86]

Answer:

1. H = 29 cm

2. θ = 44°

Step-by-step explanation:

1. We can find the height of the triangle by considering the isosceles triangle as two right triangles. The height can be found by using Pitagoras:

L^{2} = H^{2} + B^{2}

Where:

L: is the sides of the isosceles triangle = 42 cm

B: is the base = 30 cm

H: is the height =?

Then, the height is:

H = \sqrt{L^{2} - B^{2}} = \sqrt{(42 cm)^{2} - (30 cm)^{2}} = 29.4 cm = 29 cm

2. The two equal angles (θ) can be found using the following trigonometric identity:          

cos(\theta) = \frac{B}{L}

\theta = cos^{-1}(\frac{30 cm}{42 cm}) = 44.4^{\circ} = 44^{\circ}

Hence, the two equal angles are 44°.

I hope it helps you!  

3 0
3 years ago
Everyone out there stop moaning around!! Move on with your lives!! Stop posting nonsense boo-hoo c.ra.p on this!! Talk to a ther
Daniel [21]

Answer: This should be under the subject English or Art, not math.

Step-by-step explanation: Go motivation, if a little rude.

8 0
3 years ago
Read 2 more answers
The Marshall Island goby, the world's smallest fish, measures .47 inch. The striped bass, an American sport fish, is about 25.5
klemol [59]
 the answer is 150 inches
6 0
3 years ago
Solve for m. x^3×y^2(x^2×y^3×z^m/z^-5)= x^5y^5z
natta225 [31]

Answer:

M = -4

Hope I helped :D

Step-by-step explanation:

3 0
3 years ago
Cable Strength: A group of engineers developed a new design for a steel cable. They need to estimate the amount of weight the ca
KatRina [158]

Answer:

95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

Step-by-step explanation:

We are given that the engineers take a random sample of 45 cables and apply weights to each of them until they break. The mean breaking weight for the 45 cables is 768.2 lb. The standard deviation of the breaking weight for the sample is 15.1 lb.

Since, in the question it is not specified that how much confidence interval has be constructed; so we assume to be constructing of 95% confidence interval.

Firstly, the Pivotal quantity for 95% confidence interval for the population mean is given by;

                            P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean breaking weight = 768.2 lb

            s = sample standard deviation = 15.1 lb

            n = sample of cables = 45

            \mu = population mean breaking strength

Here for constructing 95% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.02 < t_4_4 < 2.02) = 0.95  {As the critical value of t at 44 degree

                                           of freedom are -2.02 & 2.02 with P = 2.5%}  

P(-2.02 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.02) = 0.95

P( -2.02 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.02 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.02 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.02 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-2.02 \times {\frac{s}{\sqrt{n} } } , \bar X+2.02 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 768.2-2.02 \times {\frac{15.1}{\sqrt{45} } } , 768.2+2.02 \times {\frac{15.1}{\sqrt{45} } } ]

                                     = [763.65 lb , 772.75 lb]

Therefore, 95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

3 0
3 years ago
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