A plane ticket to barcelona costs £175

b) The university gym opens at 9 am on Saturday mornings. One Saturday morning at 8:55 am there are 15 students outside the gym

max2010maxim [7]

Answer:

The complete question is:

At a university, 13% of students smoke.

a) Calculate the expected number of smokers in a random sample of 100 students from this university:

b) The university gym opens at 9 am on Saturday mornings. One Saturday morning at 8:55 am there are 27 students outside the gym waiting for it to open. Should you use the same approach from part (a) to calculate the expected number of smokers among these 27 students?

Part a is easy, because is a random sample, we can expect that just 13% of these 100 students to be smokers, and 13% of 100 is 13, so we can expect 13 of those 100 students to be smokers.

b) This time we do not have a random sample, our sample is a sample of 15 students who go to the gym in the early morning, so our sample is biased. (And we do not know if this bias is related to smoking or not, and how that relationship is), so we can't use the same approach that we used in the previous part.

3 0

3 years ago

Arrange the numbers in descending order 374430,802343,980377 and 230392,650863,364321

lions [1.4K]

Descending is greatest to least
980377,802343,650863,374430,364321,230392

8 0

3 years ago

X^2 -10x = 8 solve show work

likoan [24]

Answer:

Step-by-step explanation:

X^2-10x-8=0

Solve simultaneously

8 0

3 years ago

Read 2 more answers

Who ever solve it will get 40 points

jolli1 [7]

Answer:
15 miles in 75 minutes
-I don’t know what a tape diagram is so sorry I can’t answer that part-

4 0

3 years ago

Find the quotient (line over 42 is repeating)

strojnjashka [21]

The correct answer is: [C]:  " $\frac{21}{11}$ " .
_____________________________________________________

<span>Explanation:
_____________________________________________________
</span>
Let us begin by converting the:
"0.42 (with the "repeating bar on the digits, "42") " ;

into a fraction, as follows:
______________________________________________________
Let x = 0.42424242424242424242424242424242....

100x = 42.42424242424242424242424242424242....
______________________________________________________

100x = 42.42424242424242424242424242424242....
– x = 0.42424242424242424242424242424242...
______________________________________________________
99x = 42.000000000000000000000000000000.... ;

→ 99x = 42 ;

Divide each side of the equation by " 99 " ;
to isolate "x" on one side of the equation; & to solve for "x" ;
______________________________________________________
→ 99x / 99 = 42/99 = (42 ÷ 3) / (99 ÷ 3) = 14/ 33;

→ x = " $\frac{14}{33}$ " .

So; "0.42 (with a repeating bar over the digits, "42" ;

is equal to: " $\frac{14}{33}$ "
________________________________________________
So, rewrite the question/problem being asked:
________________________________________________
"Find the quotient:
________________________________________________
$\frac{14}{33}$ ÷ $\frac{2}{9}$ ;

=   $\frac{14}{33}$ * $\frac{9}{2}$ ;

Note: The "14" cancels to a "7" <span>; and</span> the "2" cancels to a "1" ;
→ {since: " 14 ÷ 2 = 7 " ; and since: " 2 ÷ 2 = 1 "} ;

Note : The "33" cancels to an "11" ; and the "9" cancels to a "3" ;
   → {since: " 33 ÷ 3 = 11 " ; and since: " 9 ÷ 3 = 3 "} ;

And we can rewrite the problem as:
____________________________________________________

" $\frac{7}{11}$ * $\frac{3}{1}$ " ;

= $\frac{(7*3)}{(11*1}$ = $\frac{21}{11}$ ;

→ which is: Answer choice: [C]: " $\frac{21}{11}$ " .
____________________________________________________

3 0

4 years ago