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Fudgin [204]
2 years ago
7

Can someone help me please

Mathematics
1 answer:
pshichka [43]2 years ago
7 0
Answer: 56 times

Pls mark brainleist i really need it
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A train leaves at 14.54 and arrives at its destination at 15.47. If the train travelled 66 km, what was it's average speed in km
JulijaS [17]

Answer: average speed of the train = 4,483.0 km/h

Step-by-step explanation:

Speed = Distance / Time

Distance = 66 km

Time = 15.47  cancelling 15, we have 60 sec added to 47 sec

         <u> - 14.54</u>

=         14.   107    60 + 47

         <u> - 14.  54</u>

<u>                     53secs</u>

53secs to hours becomes =

60 secs = 1 min

60 min= i hour

therefore 53seconds =53/3600=0.0147222hours

Speed= 66/ 0.0147222= 4,483.025

Rounding to 1 dp becomes= 4,483.0 km/h

3 0
3 years ago
Find <img src="https://tex.z-dn.net/?f=%5Csqrt%7B144%7D" id="TexFormula1" title="\sqrt{144}" alt="\sqrt{144}" align="absmiddle"
Nikolay [14]

Answer:

12

Step-by-step explanation:

The square root of 144 = 12.

12 x 12 = 144

Hope that helps!

6 0
2 years ago
Read 2 more answers
When the outlier are removed how does the mean change
Margaret [11]
The mean increases when the outlier is removed
6 0
3 years ago
John wants to make a 100 ml of 6% alcohol solution mixing a quantity of a 3% alcohol solution with an 8% alcohol solution. What
mart [117]

Answer:

-50 ml of 3% alcohol solution and 150 ml of 8% alcohol solution

Step-by-step explanation:

For us to solve this type of mixture problem, we must represent the problem in equations. This will be possible by interpreting the question.

Let the original volume of the first alcohol solution be represented with x.

The quantity of the first alcohol solution needed for the mixture is 3% of x

                   ⇒ \frac{3}{100} * x

                       = 0.03x

Let the original volume of the second alcohol solution be represented with y.

The quantity of the second alcohol solution needed for the mixture is 5% of y

                   ⇒ \frac{5}{100} * y

                       = 0.05y

The final mixture of alcohol solution is 6% of 100 ml

                 ⇒ \frac{6}{100} * 100 ml

                       = 6 ml

Sum of values of two alcohol solutions = Value of the final mixture

                     0.03x + 0.05y = 6 ml               ..........(1)

Sum of original quantity of each alcohol solution = Original volume of the of mixture

                     x + y = 100 ml                          ..........(2)      

For easy interpretation, I will be setting up a table to capture all information given in the question.

Component                       Unit Value      Quantity(ml)       Value

3% of Alcohol solution        0.03                 x                     0.03x

8% of Alcohol solution        0.08                 y                     0.08y

Mixture of 100ml of 6%        0.06               100                       6    

                                                                x + y = 100       0.03x + 0.08y =6

Looking at the equations we derived, we have two unknowns in two equations which is a simultaneous equation.

                                0.03x + 0.05y = 6 ml               ..........(1)

                                x + y = 100 ml                           ..........(2)    

Using substitution method to solve the simultaneous equation.

Making x the subject of formula from equation (2), we have,

                                x  = 100 - y                                 ..........(3)

Substituting  x  = 100 - y from equation (3) into equation (1)

                               0.03(100 - y) + 0.05y = 6  

                               3 - 0.03y + 0.05y = 6  

Rearranging the equation,            

                               0.05y - 0.03y = 6 - 3

                               0.02y = 3

                               y = \frac{3}{0.02}

                               y = 150 ml

Substituting y = 150 ml into equation (3) to get x

                              x  = 100 - 150 ml

                              x = - 50 ml

The quantity of the first alcohol solution needed for the mixture for 3% is - 50 ml

The quantity of the second alcohol solution needed for the mixture for 5% is 150 ml

This solution means 50 ml of the first alcohol solution must be removed from the mixture with 150 ml of the second alcohol solution to get a final mixture of 100 ml of 6% alcohol solution.

3 0
3 years ago
Can square root of 27 be simplified
Studentka2010 [4]
<span>Yes, square root of 27 can be simplified
</span>
\sqrt{27}= \sqrt{9*3}=3 \sqrt{3}


8 0
3 years ago
Read 2 more answers
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