19
In the first image, we are given 4 match sticks.
In the second image, we are given 7 match sticks. The difference between the match sticks is 3.
In the third image, we are given 10 match sticks. The difference between the match sticks again is 3.
If in the third image we are given 10 match sticks, and for every new image, there is another 3 match stick added, then in the sixth image, there must be 19 match sticks. Image 4: 10 + 3 = 13. Image 5: 13 + 3 = 16. Image 6: 16 + 3 = 19.
Answer = 19. Hope this helps. :)
Answer:
I believe it would be 9 hours for company 1, and 10 for company 2
Step-by-step explanation:
30 x 9 = 270 (+ the first 20) =290
25 x 10 = 250 (+ the first 40) =290
Answer:
Step-by-step explanation:
a) The maximum weight M that can be supported by a beam is jointly proportional to its width w and the square of its height h, and inversely proportional to its length L. If k represent the constant of proportionality, the expression would be
M = kwh²/L
b) if w = 4 inches, h = 6 inches, length = 12 ft
1 foot = 12 inches
12 ft = 12 × 12 = 144 inches. Therefore
L = 144 inches
M = 4800lb
Substituting these values into
M = kwh²/L, it becomes
4800 = (k × 4 × 6²)/144
4800 = k
The equation becomes
M = 4800wh²/L
c) if L = 10ft(10 × 12 = 120 inches),
h = 10 inches
w = 3 inches, then
M = 4800 × 3 × 10²/120
M = 12000 lbs
If you want to add fractions, you need to first make them like fractions, this means both fractions need to have the same denominator without changing its proportion:
7/10 = 70/100
17/100 = 17/100
Now it is the same and you can add them now because they are like fractions.
70/100 + 17/100 = 87/100
Your answer is B.
Answer:
Step-by-step explanation:
From the problem statement, we can create the following equation:
where 
is the age of James, 
is the age of Paul, and 
is the age of Dan.
From the first part of the second sentence, we can set up the following equation:
From the last part of the second sentence, we can set up the following equation:
We can substitute the second equation into the last one to get the following:
We can then substitute the last two equations in the first to solve for :
Plugging this into the other two equations will give us the remaining ages:
