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Taya2010 [7]
3 years ago
11

A firefighter places a ladder against a building. The ladder forms a 47° angle with the ground. What is the measure of the angle

between the ladder and the building?
Mathematics
2 answers:
Nookie1986 [14]3 years ago
5 0
The ladder , ground and the building form a right angled triangle

The angle that ladder makes with the building is 90-47  = 43 degrees Answer.
hodyreva [135]3 years ago
5 0

43 degrees is going to be your answer

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Let f(x)=(x+2)^2
user100 [1]
The graph if g(x) is vertically stretched by a factor of 3
Hope this helped :)
7 0
3 years ago
there is 4/5 lb of sand in science supplies. if one scoop of sand weighs 1/20 of a lb how many scoops of sand can maria get from
tatuchka [14]
We want to divide whole sand into scoops, so we have to divide 4/5 by 1/20. Lets do this

\frac{ \frac{4}{5} }{ \frac{1}{20} }
We know that if we want to divide 2 fraction we can multiply first by inverse of second fraction instead of dividing.,so:
\frac{ \frac{4}{5} }{ \frac{1}{20} }
\frac{4}{5}* \frac{20}{1}= \frac{4*20}{5*1}   = \frac{80}{5}= 16 scoops - its our result.
5 0
3 years ago
Find the two square roots of each complex number by creating and solving polynomial equations.
son4ous [18]

Answer:

1) w₁=4 - i w₂= -4 + i

2) w₁= 3 - i w₂= -3  + i

3) w₁= 1 + 2i w₂= - 1 - 2i

4) w₁= 2- 3i w₂= -2 + 3i

5) w₁= 5 - 2i w₂= -5 + 2i

6) w₁= 5 - 3i w₂= -5 + 3i

Step-by-step explanation:

The root of a complex number is given by:

\sqrt[n]{z}=\sqrt[n]{r}(Cos(\frac{\theta+2k\pi}{n}) + i Sin(\frac{\theta+2k\pi}{n}))

where:

r: is the module of the complex number

θ: is the angle of the complex number to the positive axis x

n: index of the root

1) z = 15 − 8i  ⇒ r=17 θ= -0.4899 rad

w₁=\sqrt{17}(Cos(\frac{-0.4899}{2}) + i Sin(\frac{-0.4899}{2}))=4-i

w₂=\sqrt{17}(Cos(\frac{-0.4899+2\pi}{2}) + i Sin(\frac{-0.4899+2\pi}{2}))=-1+i

2) z = 8 − 6i  ⇒ r=10 θ= -0.6435 rad

w₁=\sqrt{10}(Cos(\frac{ -0.6435}{2}) + i Sin(\frac{ -0.6435}{2}))= 3 - i

w₂=\sqrt{10}(Cos(\frac{ -0.6435+2\pi}{2}) + i Sin(\frac{ -0.6435+2\pi}{2}))= -3  + i

3) z = −3 + 4i  ⇒ r=5 θ= -0.9316 rad

w₁=\sqrt{5}(Cos(\frac{-0.9316}{2}) + i Sin(\frac{-0.9316}{2}))= 1 + 2i

w₂=\sqrt{5}(Cos(\frac{-0.9316+2\pi}{2}) + i Sin(\frac{-0.9316+2\pi}{2}))= -1 - 2i

4) z = −5 − 12i  ⇒ r=13 θ= 0.4426 rad

w₁=\sqrt{13}(Cos(\frac{0.4426}{2}) + i Sin(\frac{0.4426}{2}))= 2- 3i

w₂=\sqrt{13}(Cos(\frac{0.4426+2\pi}{2}) + i Sin(\frac{0.4426+2\pi}{2}))= -2 + 3i

5) z = 21 − 20i  ⇒ r=29 θ= -0.8098 rad

w₁=\sqrt{29}(Cos(\frac{-0.8098}{2}) + i Sin(\frac{-0.8098}{2}))= 5 - 2i

w₂=\sqrt{29}(Cos(\frac{-0.8098+2\pi}{2}) + i Sin(\frac{-0.8098+2\pi}{2}))= -5 + 2i

6) z = 16 − 30i ⇒ r=34 θ= -1.0808 rad

w₁=\sqrt{34}(Cos(\frac{-1.0808}{2}) + i Sin(\frac{-1.0808}{2}))= 5 - 3i

w₂=\sqrt{34}(Cos(\frac{-1.0808+2\pi}{2}) + i Sin(\frac{-1.0808+2\pi}{2}))= -5 + 3i

6 0
4 years ago
Please Help!!<br> Write an equation of the line that passes through each pair of points.
Alex

Answer: y=-2x + 3

Step-by-step explanation:

(0,3)   and (2,-1)

3-(-1)= 4

0-2= -2  

4/-2= -2  so the slope is -2  and we already know the y intercept is 3 because that is when x is 0.

so the equation will    y= -2x + 3

6 0
3 years ago
Please helppp!!!!!!!
rjkz [21]

Answer:

66

Step-by-step explanation:

5 0
3 years ago
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