Question

You drop a ball from a height of 1.5 meters. Each curved path has 75% of the height of the previous path. a. Write a rule for the sequence using centimeters. The initial height is given by the term n = 1. b. What height will the ball be at the top of the sixth path?

Answer 1

Answer:

a)

The rule for the sequence is given by:

        $a_n=150\cdot (0.75)^{n-1}$

b)

The height of ball at the top of sixth path is:

               35.5957 cm.

Step-by-step explanation:

a)

Let the nth term of the sequence is represented by:

                                   $a_n$

i.e. it represent the height of the ball in nth path.

It is given that:

You drop a ball from a height of 1.5 meters.

This means that the initial height of the ball is: 1.5 meters

We know that  1 meter= 100 centimeter(cm)

This means that:

           1.5 meter= 150 cm.

Hence, we have: $a_1=150$

Also, Each curved path has 75% of the height of the previous path.

This means that:

$a_2=(0.75)\cdot a_1$

$a_3=(0.75)\cdot a_2=(0.75)^2\cdot a_1$

$a_4=(0.75)\cdot a_3=(0.75)^3\cdot a_1$

and so on.

Hence, we may write the nth term in general form by:

$a_n=(0.75)^{n-1}\cdot 150$

b)

The height of the ball at the top of sixth path.

i.e. the value of $a_n$ when n=6 is:

$a_6=(0.75)^{6-1}\cdot 150\\\\i.e.\\\\a_6=(0.75)^5\cdot 150\\\\i.e.\\\\a_6=35.5957\ \text{cm}$

Answer 2

150 × (.75)^x-1 for part A

the second part is: 

33.3 cm's

I hope this helps!