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love history [14]
3 years ago
7

Can i get help right answer gets brainlyest

Mathematics
2 answers:
masha68 [24]3 years ago
7 0

Answer:  The slope is 6.

Step-by-step explanation:

One way to see the slope is to look at the graph and find places where the graphed line crosses the corners formed by the grid lines. Then count the number from top to bottom and divide that number by the number of blocks left to right  (IF the scale is the same for both the x-axis and y-axis!) Then divide up-down number by left-right number. If it is the same, the slope is 1.

Here the line crosses the y axis at -1 exactly: (0, -1) The next place where it crosses the corner exactly is at (1, 5). Counting blocks:  6 from top to bottom, only 1 left to right  6/1

Or do it with the numbers: Find the difference in y-values, them divide by the difference in x-values, Using Coordinates (0,-1) and (1,5)  the difference in y-values is 5-(-1) = 5+1 = 6 The difference in x-values is 1 - 0 = 1   6÷1 = 6

Komok [63]3 years ago
4 0

Answer:

2

Step-by-step explanation:

start counting from the y axis and when it touches the curve trace it down to X axis

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Not 100% sure but I think that it is 14.6
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A new shopping mall is considering setting up an information desk manned by one employee. Based upon information obtained from s
quester [9]

Answer:

a) P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33 and that represent the 33%

b) p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66

c) L_s =\frac{20}{30-20}=\frac{20}{10}=2 people

d) L_q =\frac{20^2}{30(30-20)}=1.333 people

e) W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours

f) W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours

Step-by-step explanation:

Notation

P represent the probability that the employee is idle

p_x represent the probability that the employee is busy

L_s represent the average number of people receiving and waiting to receive some information

L_q represent the average number of people waiting in line to get some information

W_s represent the average time a person seeking information spends in the system

W_q represent the expected time a person spends just waiting in line to have a question answered

This an special case of Single channel model

Single Channel Queuing Model. "That division of service channels happen in regards to number of servers that are present at each of the queues that are formed. Poisson distribution determines the number of arrivals on a per unit time basis, where mean arrival rate is denoted by λ".

Part a

Find the probability that the employee is idle

The probability on this case is given by:

In order to find the mean we can do this:

\mu = \frac{1question}{2minutes}\frac{60minutes}{1hr}=\frac{30 question}{hr}

And in order to find the probability we can do this:

P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33 and that represent the 33%

Part b

Find the proportion of the time that the employee is busy

This proportion is given by:

p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66

Part c

Find the average number of people receiving and waiting to receive some information

In order to find this average we can use this formula:

L_s= \frac{\lambda}{\lambda -\mu}

And replacing we got:

L_s =\frac{20}{30-20}=\frac{20}{10}=2 people

Part d

Find the average number of people waiting in line to get some information.

For the number of people wiating we can us ethe following formula"

L_q =\frac{\lambda^2}{\mu(\mu-\lambda)}

And replacing we got this:

L_q =\frac{20^2}{30(30-20)}=1.333 people

Part e

Find the average time a person seeking information spends in the system

For this average we can use the following formula:

W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours

Part f

Find the expected time a person spends just waiting in line to have a question answered (time in the queue).

For this case the waiting time to answer a question we can use this formula:

W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours

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its B

Step-by-step explanation:

math  way

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See the picture below

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Nonamiya [84]
I hope this helps you



m (ACD)=m (ABD)



4x+4=6x-14



2x=18


x=9



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